Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 398 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹16100 at 10% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹51600 at 20% per year for 1 year, compounded every year (in ₹).
3. 3.A town has 37300 people. The population grows by 10% every year. What will the population be after 1 year?
4. 4.What is the difference between the compound interest and the simple interest on ₹10000 at 25% per year for 2 years (in ₹)?
5. 5.A scooter is worth ₹28300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
6. 6.Find the compound interest on ₹57000 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.A scooter is worth ₹52700. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
8. 8.What amount will ₹53000 grow to in 3 years at 20% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹55700 at 10% per year for 2 years, compounded every year (in ₹).
10. 10.What amount will ₹2200 grow to in 1 year at 20% per year compound interest (in ₹)?
11. 11.What amount will ₹52900 grow to in 1 year at 15% per year compound interest (in ₹)?
12. 12.A scooter is worth ₹44000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
13. 13.What amount will ₹4500 grow to in 3 years at 20% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹4700 at 12% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
18. 18.A town has 31800 people. The population grows by 4% every year. What will the population be after 1 year?
19. 19.Find the compound interest on ₹36200 at 10% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹49300 at 20% per year for 2 years (in ₹)?
21. 21.What amount will ₹59000 grow to in 2 years at 20% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
23. 23.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
24. 24.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹42000 at 25% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹28400 at 5% per year for 2 years (in ₹)?
28. 28.What amount will ₹26400 grow to in 2 years at 15% per year compound interest (in ₹)?
29. 29.A scooter is worth ₹30000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
30. 30.A town has 37000 people. The population grows by 10% every year. What will the population be after 3 years?
31. 31.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
32. 32.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 30800 people. The population grows by 25% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹37600 at 25% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹19500 grow to in 1 year at 8% per year compound interest (in ₹)?
37. 37.A town has 15900 people. The population grows by 10% every year. What will the population be after 1 year?
38. 38.What is the difference between the compound interest and the simple interest on ₹56100 at 20% per year for 2 years (in ₹)?
39. 39.What amount will ₹36500 grow to in 1 year at 5% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹12100 at 4% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets