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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 403 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹18600 at 5% per year for 1 year, compounded every year (in ₹).
  2. 2.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  3. 3.A scooter is worth ₹5000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹28800 at 15% per year for 2 years (in ₹)?
  5. 5.A town has 43600 people. The population grows by 5% every year. What will the population be after 2 years?
  6. 6.Find the compound interest on ₹45000 at 10% per year for 3 years, compounded every year (in ₹).
  7. 7.What amount will ₹6000 grow to in 3 years at 10% per year compound interest (in ₹)?
  8. 8.A town has 9500 people. The population grows by 20% every year. What will the population be after 3 years?
  9. 9.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹52200 at 20% per year for 1 year, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹26100 at 12% per year for 1 year, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹19200 at 15% per year for 2 years (in ₹)?
  14. 14.A town has 14500 people. The population grows by 10% every year. What will the population be after 2 years?
  15. 15.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  16. 16.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
  17. 17.A town has 7900 people. The population grows by 12% every year. What will the population be after 1 year?
  18. 18.What amount will ₹29200 grow to in 2 years at 15% per year compound interest (in ₹)?
  19. 19.What amount will ₹55500 grow to in 3 years at 20% per year compound interest (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹56800 at 15% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹34800 at 15% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹10900 at 10% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹15900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  24. 24.What amount will ₹57600 grow to in 2 years at 25% per year compound interest (in ₹)?
  25. 25.A town has 51200 people. The population grows by 25% every year. What will the population be after 1 year?
  26. 26.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  27. 27.A scooter is worth ₹30600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  28. 28.Find the compound interest on ₹6900 at 25% per year for 1 year, compounded every year (in ₹).
  29. 29.What amount will ₹40400 grow to in 2 years at 25% per year compound interest (in ₹)?
  30. 30.What amount will ₹36300 grow to in 1 year at 25% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹34000 at 5% per year for 2 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹5300 at 20% per year for 2 years (in ₹)?
  34. 34.A scooter is worth ₹41100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹22000 at 5% per year for 2 years (in ₹)?
  36. 36.A scooter is worth ₹48100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  37. 37.A town has 14700 people. The population grows by 20% every year. What will the population be after 1 year?
  38. 38.A scooter is worth ₹11500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  39. 39.A town has 52100 people. The population grows by 12% every year. What will the population be after 1 year?
  40. 40.Find the compound interest on ₹43500 at 10% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 930
  2. 18522
  3. 3872
  4. 648
  5. 48069
  6. 14895
  7. 7986
  8. 16416
  9. 47040
  10. 10440
  11. 3132
  12. 4167
  13. 432
  14. 17545
  15. 7566
  16. 12167
  17. 8848
  18. 38617
  19. 95904
  20. 1278
  21. 783
  22. 109
  23. 13515
  24. 90000
  25. 64000
  26. 336
  27. 29376
  28. 1725
  29. 63125
  30. 45375
  31. 8
  32. 3485
  33. 212
  34. 37812
  35. 55
  36. 38480
  37. 17640
  38. 10925
  39. 58352
  40. 9135

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