Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹18600 at 5% per year for 1 year, compounded every year (in ₹).
- 2.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 3.A scooter is worth ₹5000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹28800 at 15% per year for 2 years (in ₹)?
- 5.A town has 43600 people. The population grows by 5% every year. What will the population be after 2 years?
- 6.Find the compound interest on ₹45000 at 10% per year for 3 years, compounded every year (in ₹).
- 7.What amount will ₹6000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 8.A town has 9500 people. The population grows by 20% every year. What will the population be after 3 years?
- 9.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 10.Find the compound interest on ₹52200 at 20% per year for 1 year, compounded every year (in ₹).
- 11.Find the compound interest on ₹26100 at 12% per year for 1 year, compounded every year (in ₹).
- 12.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹19200 at 15% per year for 2 years (in ₹)?
- 14.A town has 14500 people. The population grows by 10% every year. What will the population be after 2 years?
- 15.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 16.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
- 17.A town has 7900 people. The population grows by 12% every year. What will the population be after 1 year?
- 18.What amount will ₹29200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 19.What amount will ₹55500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹56800 at 15% per year for 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹34800 at 15% per year for 2 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹10900 at 10% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹15900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 24.What amount will ₹57600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 25.A town has 51200 people. The population grows by 25% every year. What will the population be after 1 year?
- 26.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 27.A scooter is worth ₹30600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 28.Find the compound interest on ₹6900 at 25% per year for 1 year, compounded every year (in ₹).
- 29.What amount will ₹40400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 30.What amount will ₹36300 grow to in 1 year at 25% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹34000 at 5% per year for 2 years, compounded every year (in ₹).
- 33.What is the difference between the compound interest and the simple interest on ₹5300 at 20% per year for 2 years (in ₹)?
- 34.A scooter is worth ₹41100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹22000 at 5% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹48100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 37.A town has 14700 people. The population grows by 20% every year. What will the population be after 1 year?
- 38.A scooter is worth ₹11500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 39.A town has 52100 people. The population grows by 12% every year. What will the population be after 1 year?
- 40.Find the compound interest on ₹43500 at 10% per year for 2 years, compounded every year (in ₹).
Answer key
- 930
- 18522
- 3872
- 648
- 48069
- 14895
- 7986
- 16416
- 47040
- 10440
- 3132
- 4167
- 432
- 17545
- 7566
- 12167
- 8848
- 38617
- 95904
- 1278
- 783
- 109
- 13515
- 90000
- 64000
- 336
- 29376
- 1725
- 63125
- 45375
- 8
- 3485
- 212
- 37812
- 55
- 38480
- 17640
- 10925
- 58352
- 9135
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