Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 409 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹20000 at 12% per year for 2 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹11500 at 10% per year for 2 years (in ₹)?
3. 3.A town has 45700 people. The population grows by 25% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
5. 5.What amount will ₹15900 grow to in 1 year at 8% per year compound interest (in ₹)?
6. 6.What amount will ₹14600 grow to in 1 year at 15% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹9100 at 10% per year for 2 years (in ₹)?
8. 8.What amount will ₹22400 grow to in 3 years at 25% per year compound interest (in ₹)?
9. 9.A town has 10300 people. The population grows by 20% every year. What will the population be after 2 years?
10. 10.Find the compound interest on ₹32500 at 8% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
12. 12.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
13. 13.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
14. 14.What amount will ₹7600 grow to in 1 year at 12% per year compound interest (in ₹)?
15. 15.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹36200 at 8% per year for 1 year, compounded every year (in ₹).
17. 17.A town has 60000 people. The population grows by 12% every year. What will the population be after 2 years?
18. 18.What amount will ₹48000 grow to in 3 years at 25% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹19600 at 20% per year for 2 years (in ₹)?
20. 20.A scooter is worth ₹37000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
21. 21.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹31000 at 10% per year for 3 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹45100 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.What amount will ₹39300 grow to in 1 year at 25% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹16700 at 25% per year for 1 year, compounded every year (in ₹).
26. 26.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
28. 28.A scooter is worth ₹25300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
29. 29.Find the compound interest on ₹46000 at 25% per year for 2 years, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹27600 at 25% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹59500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
32. 32.What amount will ₹53300 grow to in 1 year at 4% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 10400 people. The population grows by 20% every year. What will the population be after 1 year?
35. 35.Find the compound interest on ₹34300 at 4% per year for 1 year, compounded every year (in ₹).
36. 36.A town has 43800 people. The population grows by 8% every year. What will the population be after 1 year?
37. 37.What amount will ₹14800 grow to in 2 years at 15% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹38000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
39. 39.A scooter is worth ₹17600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
40. 40.A scooter is worth ₹14700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?

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