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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 410 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹10000 at 8% per year for 1 year, compounded every year (in ₹).
  2. 2.What amount will ₹25200 grow to in 2 years at 15% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  5. 5.What amount will ₹38500 grow to in 3 years at 20% per year compound interest (in ₹)?
  6. 6.A town has 10200 people. The population grows by 25% every year. What will the population be after 1 year?
  7. 7.A scooter is worth ₹10200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹47200 at 5% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹47900 at 10% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹35200 at 15% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹40900 at 5% per year for 1 year, compounded every year (in ₹).
  13. 13.What amount will ₹12400 grow to in 1 year at 5% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹6200 at 5% per year for 1 year, compounded every year (in ₹).
  15. 15.A town has 4300 people. The population grows by 20% every year. What will the population be after 2 years?
  16. 16.What amount will ₹23300 grow to in 2 years at 10% per year compound interest (in ₹)?
  17. 17.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
  18. 18.What is the difference between the compound interest and the simple interest on ₹55600 at 5% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
  20. 20.What amount will ₹39000 grow to in 3 years at 10% per year compound interest (in ₹)?
  21. 21.What amount will ₹58000 grow to in 2 years at 5% per year compound interest (in ₹)?
  22. 22.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  24. 24.What amount will ₹53000 grow to in 1 year at 5% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹12500 at 20% per year for 2 years, compounded every year (in ₹).
  29. 29.What amount will ₹51900 grow to in 2 years at 10% per year compound interest (in ₹)?
  30. 30.A town has 8800 people. The population grows by 25% every year. What will the population be after 2 years?
  31. 31.Find the compound interest on ₹22000 at 25% per year for 1 year, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹49200 at 25% per year for 1 year, compounded every year (in ₹).
  33. 33.A scooter is worth ₹23700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  34. 34.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
  35. 35.A town has 8000 people. The population grows by 25% every year. What will the population be after 3 years?
  36. 36.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  37. 37.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  38. 38.What amount will ₹22900 grow to in 1 year at 20% per year compound interest (in ₹)?
  39. 39.What amount will ₹40000 grow to in 3 years at 20% per year compound interest (in ₹)?
  40. 40.A scooter is worth ₹5000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 800
  2. 33327
  3. 304
  4. 384
  5. 66528
  6. 12750
  7. 9792
  8. 118
  9. 479
  10. 792
  11. 39650
  12. 2045
  13. 13020
  14. 310
  15. 6192
  16. 28193
  17. 72128
  18. 139
  19. 8
  20. 51909
  21. 63945
  22. 37044
  23. 192
  24. 55650
  25. 8334
  26. 84
  27. 324
  28. 5500
  29. 62799
  30. 13750
  31. 5500
  32. 12300
  33. 22752
  34. 28975
  35. 15625
  36. 368
  37. 60835
  38. 27480
  39. 69120
  40. 4232

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