Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 413 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹22100 at 4% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹14100 at 20% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹8000 at 15% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹42900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
5. 5.Find the compound interest on ₹55000 at 20% per year for 1 year, compounded every year (in ₹).
6. 6.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
7. 7.What amount will ₹39300 grow to in 1 year at 4% per year compound interest (in ₹)?
8. 8.What amount will ₹24100 grow to in 1 year at 10% per year compound interest (in ₹)?
9. 9.A scooter is worth ₹43600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
10. 10.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
11. 11.A scooter is worth ₹21200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹10500 at 15% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹27200 at 5% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹22200 at 20% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹47600 at 5% per year for 2 years, compounded every year (in ₹).
19. 19.Find the compound interest on ₹7600 at 10% per year for 2 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹37700 at 8% per year for 1 year, compounded every year (in ₹).
21. 21.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
22. 22.A town has 34800 people. The population grows by 15% every year. What will the population be after 1 year?
23. 23.A town has 24800 people. The population grows by 25% every year. What will the population be after 2 years?
24. 24.What amount will ₹38800 grow to in 1 year at 20% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹20800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹8700 at 20% per year for 2 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹33000 at 10% per year for 1 year, compounded every year (in ₹).
29. 29.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹22100 at 10% per year for 2 years (in ₹)?
31. 31.What amount will ₹11400 grow to in 2 years at 20% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹21000 at 10% per year for 3 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹5700 at 15% per year for 1 year, compounded every year (in ₹).
34. 34.Find the compound interest on ₹22300 at 20% per year for 2 years, compounded every year (in ₹).
35. 35.A town has 57600 people. The population grows by 25% every year. What will the population be after 1 year?
36. 36.What amount will ₹57100 grow to in 1 year at 4% per year compound interest (in ₹)?
37. 37.A town has 8100 people. The population grows by 25% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹52700 at 10% per year for 2 years, compounded every year (in ₹).
39. 39.A town has 28400 people. The population grows by 25% every year. What will the population be after 1 year?
40. 40.Find the compound interest on ₹46800 at 5% per year for 2 years, compounded every year (in ₹).

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