Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹42500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 2.A town has 50000 people. The population grows by 4% every year. What will the population be after 2 years?
- 3.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 4.What amount will ₹17200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 5.A scooter is worth ₹15100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 6.What amount will ₹52800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 7.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
- 9.What amount will ₹21500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 10.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
- 12.A scooter is worth ₹42600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 13.What amount will ₹42500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹8000 at 10% per year for 3 years, compounded every year (in ₹).
- 15.What amount will ₹31100 grow to in 1 year at 8% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹31600 at 25% per year for 2 years (in ₹)?
- 17.A scooter is worth ₹17800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹27800 at 10% per year for 2 years (in ₹)?
- 19.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 20.A scooter is worth ₹10000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 21.A town has 44100 people. The population grows by 15% every year. What will the population be after 1 year?
- 22.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹37000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 24.A scooter is worth ₹9600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 25.What amount will ₹12400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹8400 at 25% per year for 2 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 28.A town has 22400 people. The population grows by 15% every year. What will the population be after 2 years?
- 29.Find the compound interest on ₹56300 at 5% per year for 1 year, compounded every year (in ₹).
- 30.A town has 27200 people. The population grows by 10% every year. What will the population be after 2 years?
- 31.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
- 32.A town has 35000 people. The population grows by 4% every year. What will the population be after 2 years?
- 33.What amount will ₹25000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 34.A town has 9800 people. The population grows by 25% every year. What will the population be after 1 year?
- 35.What amount will ₹2000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹15400 at 10% per year for 1 year, compounded every year (in ₹).
- 37.A town has 21000 people. The population grows by 20% every year. What will the population be after 3 years?
- 38.A scooter is worth ₹55000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
Answer key
- 21760
- 54080
- 3783
- 20812
- 13892
- 103125
- 46305
- 76
- 37152
- 2916
- 4896
- 27264
- 45968
- 2648
- 33588
- 1975
- 15664
- 278
- 18522
- 7744
- 50715
- 16
- 26973
- 4050
- 13671
- 4725
- 720
- 29624
- 2815
- 32912
- 56
- 37856
- 31360
- 12250
- 2205
- 1540
- 36288
- 28160
- 108
- 240
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