Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 415 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹37200 at 15% per year for 2 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹24800 at 15% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹16100 at 20% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹40500 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.What amount will ₹33300 grow to in 1 year at 4% per year compound interest (in ₹)?
8. 8.What amount will ₹53200 grow to in 1 year at 5% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹40800 at 15% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
11. 11.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹17600 at 15% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹59200 at 5% per year for 2 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
16. 16.A town has 51600 people. The population grows by 8% every year. What will the population be after 1 year?
17. 17.A scooter is worth ₹7900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹9600 at 10% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹10000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹8000 at 25% per year for 2 years (in ₹)?
21. 21.A scooter is worth ₹46900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
22. 22.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
23. 23.What amount will ₹56800 grow to in 2 years at 15% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
25. 25.Find the compound interest on ₹7700 at 15% per year for 1 year, compounded every year (in ₹).
26. 26.A town has 38900 people. The population grows by 10% every year. What will the population be after 2 years?
27. 27.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹54000 at 25% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹49200 at 15% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹38600 at 10% per year for 2 years (in ₹)?
31. 31.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
32. 32.A town has 57500 people. The population grows by 8% every year. What will the population be after 2 years?
33. 33.What amount will ₹5400 grow to in 1 year at 25% per year compound interest (in ₹)?
34. 34.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
35. 35.Find the compound interest on ₹33600 at 20% per year for 2 years, compounded every year (in ₹).
36. 36.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
37. 37.What amount will ₹26000 grow to in 2 years at 5% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹36000 at 25% per year for 2 years (in ₹)?
40. 40.What amount will ₹43300 grow to in 1 year at 4% per year compound interest (in ₹)?

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