Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
- 2.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 3.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
- 4.Find the compound interest on ₹26500 at 10% per year for 2 years, compounded every year (in ₹).
- 5.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 6.A town has 17600 people. The population grows by 25% every year. What will the population be after 3 years?
- 7.What amount will ₹12100 grow to in 1 year at 15% per year compound interest (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹29200 at 15% per year for 2 years (in ₹)?
- 9.What amount will ₹33700 grow to in 1 year at 5% per year compound interest (in ₹)?
- 10.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 11.A scooter is worth ₹12400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 12.Find the compound interest on ₹59000 at 10% per year for 3 years, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹5600 at 25% per year for 2 years (in ₹)?
- 14.A scooter is worth ₹10400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹2400 at 25% per year for 2 years (in ₹)?
- 16.A scooter is worth ₹18400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 17.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
- 18.What amount will ₹17200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 19.A scooter is worth ₹18700. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹22000 at 10% per year for 2 years (in ₹)?
- 23.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 24.Find the compound interest on ₹24100 at 20% per year for 1 year, compounded every year (in ₹).
- 25.What amount will ₹53500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 26.What amount will ₹44000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹59000 at 8% per year for 1 year, compounded every year (in ₹).
- 28.Find the compound interest on ₹14500 at 20% per year for 1 year, compounded every year (in ₹).
- 29.What amount will ₹4000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 30.What amount will ₹48000 grow to in 1 year at 4% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹52600 at 8% per year for 1 year, compounded every year (in ₹).
- 33.What amount will ₹31600 grow to in 1 year at 5% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹7100 at 10% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
- 38.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
- 39.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 40.What amount will ₹49600 grow to in 1 year at 12% per year compound interest (in ₹)?
Answer key
- 2080
- 336
- 55404
- 5565
- 37044
- 34375
- 13915
- 657
- 35385
- 46305
- 6975
- 19529
- 350
- 9568
- 150
- 16928
- 9261
- 22747
- 14960
- 468
- 20
- 220
- 109375
- 4820
- 58850
- 47520
- 4720
- 2900
- 4410
- 49920
- 16
- 4208
- 33180
- 48
- 71
- 1655
- 180
- 46305
- 7566
- 55552
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