Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 417 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹29000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
2. 2.A scooter is worth ₹5800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
3. 3.What amount will ₹45500 grow to in 1 year at 4% per year compound interest (in ₹)?
4. 4.What amount will ₹36900 grow to in 1 year at 5% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹38400 at 25% per year for 3 years, compounded every year (in ₹).
6. 6.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
9. 9.What amount will ₹24000 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.A town has 17500 people. The population grows by 20% every year. What will the population be after 3 years?
11. 11.Find the compound interest on ₹56400 at 20% per year for 1 year, compounded every year (in ₹).
12. 12.A scooter is worth ₹24800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
13. 13.A town has 4700 people. The population grows by 15% every year. What will the population be after 1 year?
14. 14.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
15. 15.What amount will ₹11800 grow to in 1 year at 25% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹25300 at 5% per year for 1 year, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹34800 at 5% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹27500 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
21. 21.A scooter is worth ₹53700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
22. 22.What amount will ₹41500 grow to in 2 years at 10% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹9200 at 5% per year for 2 years (in ₹)?
24. 24.What amount will ₹17000 grow to in 3 years at 20% per year compound interest (in ₹)?
25. 25.What amount will ₹4600 grow to in 1 year at 10% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
27. 27.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
28. 28.A scooter is worth ₹44500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
29. 29.Find the compound interest on ₹52100 at 12% per year for 1 year, compounded every year (in ₹).
30. 30.A town has 52300 people. The population grows by 4% every year. What will the population be after 1 year?
31. 31.Find the compound interest on ₹35500 at 20% per year for 3 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
33. 33.Find the compound interest on ₹58900 at 20% per year for 1 year, compounded every year (in ₹).
34. 34.Find the compound interest on ₹52900 at 5% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹41500 at 12% per year for 1 year, compounded every year (in ₹).
36. 36.A town has 23400 people. The population grows by 10% every year. What will the population be after 2 years?
37. 37.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
38. 38.A town has 57600 people. The population grows by 4% every year. What will the population be after 1 year?
39. 39.Find the compound interest on ₹22500 at 4% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹9100 at 20% per year for 2 years (in ₹)?

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