Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 418 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹54700 at 10% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹46200 at 25% per year for 1 year, compounded every year (in ₹).
3. 3.A town has 23600 people. The population grows by 25% every year. What will the population be after 2 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
5. 5.A town has 32000 people. The population grows by 10% every year. What will the population be after 3 years?
6. 6.What is the difference between the compound interest and the simple interest on ₹40000 at 20% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹48000 at 25% per year for 3 years, compounded every year (in ₹).
8. 8.A scooter is worth ₹12400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
9. 9.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
10. 10.What amount will ₹37200 grow to in 2 years at 5% per year compound interest (in ₹)?
11. 11.A scooter is worth ₹18500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
12. 12.Find the compound interest on ₹39500 at 20% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹2300 at 15% per year for 1 year, compounded every year (in ₹).
14. 14.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹50600 at 15% per year for 1 year, compounded every year (in ₹).
16. 16.A scooter is worth ₹27200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹28200 at 12% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
20. 20.What amount will ₹58500 grow to in 3 years at 20% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹58400 at 15% per year for 2 years (in ₹)?
22. 22.A town has 27000 people. The population grows by 4% every year. What will the population be after 1 year?
23. 23.What amount will ₹44800 grow to in 2 years at 15% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹17800 at 10% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹4300 at 20% per year for 2 years, compounded every year (in ₹).
27. 27.A scooter is worth ₹48700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹51700 at 10% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹27600 at 10% per year for 2 years, compounded every year (in ₹).
30. 30.A town has 26000 people. The population grows by 15% every year. What will the population be after 2 years?
31. 31.A scooter is worth ₹5000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
32. 32.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 15000 people. The population grows by 10% every year. What will the population be after 3 years?
35. 35.Find the compound interest on ₹21900 at 5% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹32500 at 10% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 5000 people. The population grows by 15% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
39. 39.A scooter is worth ₹47600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
40. 40.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).

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