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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 419 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹28400 at 5% per year for 2 years (in ₹)?
  2. 2.A town has 12600 people. The population grows by 5% every year. What will the population be after 1 year?
  3. 3.Find the compound interest on ₹37900 at 20% per year for 1 year, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹26800 at 5% per year for 1 year, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹26000 at 20% per year for 2 years (in ₹)?
  6. 6.What amount will ₹39000 grow to in 3 years at 10% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
  8. 8.A scooter is worth ₹35000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹57100 at 8% per year for 1 year, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹22000 at 20% per year for 3 years, compounded every year (in ₹).
  12. 12.A town has 15500 people. The population grows by 20% every year. What will the population be after 3 years?
  13. 13.What is the difference between the compound interest and the simple interest on ₹59200 at 25% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹32500 at 10% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹28800 at 15% per year for 2 years (in ₹)?
  16. 16.What amount will ₹19400 grow to in 2 years at 20% per year compound interest (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹13200 at 5% per year for 2 years (in ₹)?
  19. 19.A town has 8900 people. The population grows by 12% every year. What will the population be after 1 year?
  20. 20.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
  21. 21.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  22. 22.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹39200 at 10% per year for 2 years (in ₹)?
  24. 24.A town has 43200 people. The population grows by 15% every year. What will the population be after 2 years?
  25. 25.What amount will ₹8700 grow to in 2 years at 10% per year compound interest (in ₹)?
  26. 26.What amount will ₹14700 grow to in 1 year at 4% per year compound interest (in ₹)?
  27. 27.A town has 8700 people. The population grows by 10% every year. What will the population be after 2 years?
  28. 28.A scooter is worth ₹52500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹44800 at 25% per year for 2 years (in ₹)?
  30. 30.What amount will ₹20500 grow to in 3 years at 20% per year compound interest (in ₹)?
  31. 31.What amount will ₹56900 grow to in 2 years at 20% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹48000 at 5% per year for 2 years (in ₹)?
  33. 33.A town has 58100 people. The population grows by 10% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹46900 at 5% per year for 1 year, compounded every year (in ₹).
  35. 35.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  36. 36.A scooter is worth ₹53800. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  37. 37.What amount will ₹4000 grow to in 3 years at 10% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹34300 at 20% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹37700 at 20% per year for 2 years (in ₹)?
  40. 40.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 71
  2. 13230
  3. 7580
  4. 1340
  5. 1040
  6. 51909
  7. 112
  8. 27104
  9. 67
  10. 4568
  11. 16016
  12. 26784
  13. 3700
  14. 3250
  15. 648
  16. 27936
  17. 80
  18. 33
  19. 9968
  20. 10923
  21. 20577
  22. 4452
  23. 392
  24. 57132
  25. 10527
  26. 15288
  27. 10527
  28. 44436
  29. 2800
  30. 35424
  31. 81936
  32. 120
  33. 70301
  34. 2345
  35. 55566
  36. 45730
  37. 5324
  38. 1372
  39. 1508
  40. 19044

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