Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹28400 at 5% per year for 2 years (in ₹)?
- 2.A town has 12600 people. The population grows by 5% every year. What will the population be after 1 year?
- 3.Find the compound interest on ₹37900 at 20% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹26800 at 5% per year for 1 year, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹26000 at 20% per year for 2 years (in ₹)?
- 6.What amount will ₹39000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
- 8.A scooter is worth ₹35000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹57100 at 8% per year for 1 year, compounded every year (in ₹).
- 11.Find the compound interest on ₹22000 at 20% per year for 3 years, compounded every year (in ₹).
- 12.A town has 15500 people. The population grows by 20% every year. What will the population be after 3 years?
- 13.What is the difference between the compound interest and the simple interest on ₹59200 at 25% per year for 2 years (in ₹)?
- 14.Find the compound interest on ₹32500 at 10% per year for 1 year, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹28800 at 15% per year for 2 years (in ₹)?
- 16.What amount will ₹19400 grow to in 2 years at 20% per year compound interest (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹13200 at 5% per year for 2 years (in ₹)?
- 19.A town has 8900 people. The population grows by 12% every year. What will the population be after 1 year?
- 20.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
- 21.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 22.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
- 23.What is the difference between the compound interest and the simple interest on ₹39200 at 10% per year for 2 years (in ₹)?
- 24.A town has 43200 people. The population grows by 15% every year. What will the population be after 2 years?
- 25.What amount will ₹8700 grow to in 2 years at 10% per year compound interest (in ₹)?
- 26.What amount will ₹14700 grow to in 1 year at 4% per year compound interest (in ₹)?
- 27.A town has 8700 people. The population grows by 10% every year. What will the population be after 2 years?
- 28.A scooter is worth ₹52500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹44800 at 25% per year for 2 years (in ₹)?
- 30.What amount will ₹20500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 31.What amount will ₹56900 grow to in 2 years at 20% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹48000 at 5% per year for 2 years (in ₹)?
- 33.A town has 58100 people. The population grows by 10% every year. What will the population be after 2 years?
- 34.Find the compound interest on ₹46900 at 5% per year for 1 year, compounded every year (in ₹).
- 35.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
- 36.A scooter is worth ₹53800. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 37.What amount will ₹4000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹34300 at 20% per year for 2 years (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹37700 at 20% per year for 2 years (in ₹)?
- 40.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
Answer key
- 71
- 13230
- 7580
- 1340
- 1040
- 51909
- 112
- 27104
- 67
- 4568
- 16016
- 26784
- 3700
- 3250
- 648
- 27936
- 80
- 33
- 9968
- 10923
- 20577
- 4452
- 392
- 57132
- 10527
- 15288
- 10527
- 44436
- 2800
- 35424
- 81936
- 120
- 70301
- 2345
- 55566
- 45730
- 5324
- 1372
- 1508
- 19044
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets