Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 420 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹50000 at 4% per year for 2 years, compounded every year (in ₹).
2. 2.What amount will ₹36800 grow to in 2 years at 5% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹8000 at 10% per year for 2 years (in ₹)?
4. 4.A town has 42900 people. The population grows by 12% every year. What will the population be after 1 year?
5. 5.Find the compound interest on ₹15500 at 10% per year for 1 year, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹42500 at 10% per year for 2 years (in ₹)?
7. 7.A town has 30800 people. The population grows by 20% every year. What will the population be after 1 year?
8. 8.What amount will ₹41200 grow to in 2 years at 25% per year compound interest (in ₹)?
9. 9.A scooter is worth ₹6300. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
10. 10.A town has 17200 people. The population grows by 15% every year. What will the population be after 2 years?
11. 11.What is the difference between the compound interest and the simple interest on ₹45200 at 20% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹10000 at 5% per year for 2 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹53400 at 10% per year for 2 years (in ₹)?
14. 14.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
16. 16.What amount will ₹5600 grow to in 2 years at 5% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹26000 at 15% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹15100 at 20% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
20. 20.A town has 5000 people. The population grows by 8% every year. What will the population be after 2 years?
21. 21.What amount will ₹9400 grow to in 1 year at 20% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹32300 at 12% per year for 1 year, compounded every year (in ₹).
24. 24.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹24000 at 25% per year for 3 years, compounded every year (in ₹).
26. 26.A town has 50000 people. The population grows by 4% every year. What will the population be after 2 years?
27. 27.What is the difference between the compound interest and the simple interest on ₹36400 at 25% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹33500 at 10% per year for 2 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹32000 at 5% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹58000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹47600 at 5% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹36000 at 10% per year for 3 years, compounded every year (in ₹).
35. 35.A town has 10900 people. The population grows by 10% every year. What will the population be after 2 years?
36. 36.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹43300 at 10% per year for 2 years, compounded every year (in ₹).
38. 38.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹23100 at 20% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹58800 at 15% per year for 2 years (in ₹)?

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