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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 42 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹55000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  2. 2.What amount will ₹6000 grow to in 1 year at 5% per year compound interest (in ₹)?
  3. 3.A town has 42600 people. The population grows by 25% every year. What will the population be after 1 year?
  4. 4.A town has 59200 people. The population grows by 25% every year. What will the population be after 1 year?
  5. 5.What amount will ₹7500 grow to in 2 years at 4% per year compound interest (in ₹)?
  6. 6.What amount will ₹42000 grow to in 3 years at 20% per year compound interest (in ₹)?
  7. 7.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹2400 at 5% per year for 2 years (in ₹)?
  9. 9.What amount will ₹30100 grow to in 1 year at 10% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹57100 at 8% per year for 1 year, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹8200 at 10% per year for 2 years (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
  13. 13.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹44000 at 25% per year for 2 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹47500 at 12% per year for 2 years, compounded every year (in ₹).
  17. 17.What amount will ₹9000 grow to in 1 year at 15% per year compound interest (in ₹)?
  18. 18.A town has 17000 people. The population grows by 10% every year. What will the population be after 3 years?
  19. 19.What is the difference between the compound interest and the simple interest on ₹2800 at 20% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹26300 at 10% per year for 2 years, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹45100 at 4% per year for 1 year, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹28000 at 20% per year for 2 years (in ₹)?
  23. 23.What amount will ₹43600 grow to in 2 years at 15% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹23200 at 15% per year for 1 year, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  26. 26.What amount will ₹47400 grow to in 1 year at 5% per year compound interest (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
  29. 29.What amount will ₹57500 grow to in 2 years at 8% per year compound interest (in ₹)?
  30. 30.What amount will ₹9200 grow to in 2 years at 10% per year compound interest (in ₹)?
  31. 31.What amount will ₹19900 grow to in 1 year at 20% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹5200 at 5% per year for 2 years (in ₹)?
  33. 33.What amount will ₹18500 grow to in 3 years at 20% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹11400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  35. 35.Find the compound interest on ₹10100 at 4% per year for 1 year, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
  38. 38.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  39. 39.What amount will ₹31200 grow to in 2 years at 10% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?

Answer key

  1. 46552
  2. 6300
  3. 53250
  4. 74000
  5. 8112
  6. 72576
  7. 612
  8. 6
  9. 33110
  10. 4568
  11. 82
  12. 40
  13. 5408
  14. 612
  15. 24750
  16. 12084
  17. 10350
  18. 22627
  19. 112
  20. 5523
  21. 1804
  22. 1120
  23. 57661
  24. 3480
  25. 180
  26. 49770
  27. 25
  28. 7625
  29. 67068
  30. 11132
  31. 23880
  32. 13
  33. 31968
  34. 10488
  35. 404
  36. 103
  37. 414
  38. 34295
  39. 37752
  40. 504

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