Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 430 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹37700 grow to in 1 year at 12% per year compound interest (in ₹)?
2. 2.What amount will ₹51600 grow to in 2 years at 15% per year compound interest (in ₹)?
3. 3.What amount will ₹10500 grow to in 2 years at 10% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹39900 at 10% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹19400 at 20% per year for 2 years (in ₹)?
6. 6.A town has 25200 people. The population grows by 15% every year. What will the population be after 2 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹44200 at 10% per year for 2 years (in ₹)?
8. 8.What amount will ₹22000 grow to in 2 years at 25% per year compound interest (in ₹)?
9. 9.A scooter is worth ₹45900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹22400 at 25% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹35100 at 10% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹57800 at 10% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹34400 at 5% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹45600 grow to in 1 year at 8% per year compound interest (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹12900 at 10% per year for 2 years (in ₹)?
17. 17.A town has 58100 people. The population grows by 10% every year. What will the population be after 1 year?
18. 18.Find the compound interest on ₹48500 at 5% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 32000 people. The population grows by 15% every year. What will the population be after 2 years?
20. 20.A town has 22500 people. The population grows by 12% every year. What will the population be after 2 years?
21. 21.A scooter is worth ₹37200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹28600 at 20% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
25. 25.What amount will ₹5500 grow to in 1 year at 20% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹54500 at 8% per year for 1 year, compounded every year (in ₹).
28. 28.What amount will ₹51600 grow to in 1 year at 8% per year compound interest (in ₹)?
29. 29.What amount will ₹58000 grow to in 3 years at 10% per year compound interest (in ₹)?
30. 30.A town has 48900 people. The population grows by 25% every year. What will the population be after 1 year?
31. 31.Find the compound interest on ₹54200 at 5% per year for 1 year, compounded every year (in ₹).
32. 32.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
33. 33.What amount will ₹17500 grow to in 1 year at 8% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹30100 at 10% per year for 2 years, compounded every year (in ₹).
35. 35.What amount will ₹41500 grow to in 1 year at 4% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹9500 at 15% per year for 1 year, compounded every year (in ₹).
37. 37.A town has 42400 people. The population grows by 5% every year. What will the population be after 2 years?
38. 38.A town has 23900 people. The population grows by 15% every year. What will the population be after 1 year?
39. 39.Find the compound interest on ₹31000 at 20% per year for 3 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹26400 at 8% per year for 1 year, compounded every year (in ₹).

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