Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 433 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 27100 people. The population grows by 10% every year. What will the population be after 2 years?
2. 2.A town has 4400 people. The population grows by 25% every year. What will the population be after 2 years?
3. 3.What amount will ₹49600 grow to in 1 year at 15% per year compound interest (in ₹)?
4. 4.A town has 4900 people. The population grows by 4% every year. What will the population be after 1 year?
5. 5.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹44500 at 10% per year for 2 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹59900 at 10% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹49900 at 10% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹57500 at 12% per year for 2 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹56400 at 15% per year for 2 years (in ₹)?
13. 13.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
14. 14.What amount will ₹50900 grow to in 1 year at 15% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
16. 16.What amount will ₹27200 grow to in 2 years at 5% per year compound interest (in ₹)?
17. 17.What amount will ₹48400 grow to in 2 years at 15% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹2900 at 4% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹29600 at 25% per year for 2 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹31300 at 8% per year for 1 year, compounded every year (in ₹).
21. 21.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹27600 at 20% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹39700 at 10% per year for 2 years, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹37600 at 10% per year for 2 years (in ₹)?
25. 25.What amount will ₹51800 grow to in 1 year at 5% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹6400 at 25% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹51600 at 5% per year for 2 years, compounded every year (in ₹).
28. 28.A scooter is worth ₹22500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
29. 29.What amount will ₹32400 grow to in 1 year at 8% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹5500 at 20% per year for 3 years, compounded every year (in ₹).
31. 31.A scooter is worth ₹48500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
32. 32.Find the compound interest on ₹17900 at 5% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹27200 grow to in 3 years at 25% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
35. 35.What amount will ₹49600 grow to in 1 year at 20% per year compound interest (in ₹)?
36. 36.A town has 44100 people. The population grows by 12% every year. What will the population be after 1 year?
37. 37.Find the compound interest on ₹9600 at 5% per year for 2 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹47000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
40. 40.A town has 10900 people. The population grows by 10% every year. What will the population be after 1 year?

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