Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 438 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹52100 at 10% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹14000 at 10% per year for 3 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹25400 at 10% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹57000 at 10% per year for 2 years (in ₹)?
9. 9.What amount will ₹25000 grow to in 2 years at 12% per year compound interest (in ₹)?
10. 10.A town has 53100 people. The population grows by 10% every year. What will the population be after 2 years?
11. 11.What amount will ₹40400 grow to in 2 years at 25% per year compound interest (in ₹)?
12. 12.A town has 46000 people. The population grows by 10% every year. What will the population be after 3 years?
13. 13.A scooter is worth ₹24000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
14. 14.What amount will ₹17600 grow to in 2 years at 5% per year compound interest (in ₹)?
15. 15.A town has 36300 people. The population grows by 25% every year. What will the population be after 1 year?
16. 16.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
17. 17.A town has 49100 people. The population grows by 20% every year. What will the population be after 2 years?
18. 18.What amount will ₹5500 grow to in 1 year at 15% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹21000 at 12% per year for 1 year, compounded every year (in ₹).
20. 20.What amount will ₹38300 grow to in 1 year at 8% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹11300 at 15% per year for 1 year, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹42800 at 10% per year for 2 years (in ₹)?
24. 24.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
25. 25.A scooter is worth ₹10400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
27. 27.A scooter is worth ₹28900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
28. 28.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
29. 29.What amount will ₹27000 grow to in 1 year at 15% per year compound interest (in ₹)?
30. 30.What amount will ₹55600 grow to in 2 years at 5% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹5300 at 8% per year for 1 year, compounded every year (in ₹).
32. 32.Find the compound interest on ₹32800 at 15% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹14300 at 10% per year for 2 years, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹11200 at 5% per year for 2 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹42800 at 5% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹30100 at 10% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 5000 people. The population grows by 12% every year. What will the population be after 2 years?
38. 38.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹57100 at 4% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).

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