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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 439 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
  2. 2.Find the compound interest on ₹57500 at 25% per year for 1 year, compounded every year (in ₹).
  3. 3.What amount will ₹25700 grow to in 1 year at 4% per year compound interest (in ₹)?
  4. 4.A scooter is worth ₹40800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹31200 at 15% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹23400 at 10% per year for 2 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
  8. 8.What amount will ₹47200 grow to in 2 years at 25% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹13600 at 25% per year for 2 years (in ₹)?
  10. 10.A scooter is worth ₹10500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  11. 11.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹5200 at 25% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹14000 at 25% per year for 2 years (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹38900 at 20% per year for 2 years (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
  16. 16.A scooter is worth ₹30000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  17. 17.A scooter is worth ₹56400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  18. 18.Find the compound interest on ₹24100 at 20% per year for 2 years, compounded every year (in ₹).
  19. 19.A scooter is worth ₹38600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  21. 21.What amount will ₹13600 grow to in 2 years at 25% per year compound interest (in ₹)?
  22. 22.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  23. 23.A town has 22000 people. The population grows by 4% every year. What will the population be after 1 year?
  24. 24.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹34000 at 25% per year for 2 years (in ₹)?
  26. 26.A town has 57500 people. The population grows by 4% every year. What will the population be after 1 year?
  27. 27.What is the difference between the compound interest and the simple interest on ₹5900 at 10% per year for 2 years (in ₹)?
  28. 28.What amount will ₹52800 grow to in 3 years at 25% per year compound interest (in ₹)?
  29. 29.A town has 2500 people. The population grows by 12% every year. What will the population be after 2 years?
  30. 30.Find the compound interest on ₹40600 at 15% per year for 1 year, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹21300 at 10% per year for 2 years, compounded every year (in ₹).
  32. 32.What amount will ₹47100 grow to in 1 year at 20% per year compound interest (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹25800 at 20% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹27200 at 25% per year for 3 years, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹12700 at 4% per year for 1 year, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹12400 at 20% per year for 1 year, compounded every year (in ₹).
  37. 37.What amount will ₹18400 grow to in 2 years at 25% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹60000 at 15% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹40800 at 5% per year for 2 years (in ₹)?
  40. 40.A town has 8000 people. The population grows by 10% every year. What will the population be after 3 years?

Answer key

  1. 18816
  2. 14375
  3. 26728
  4. 22950
  5. 702
  6. 4914
  7. 64
  8. 73750
  9. 850
  10. 5376
  11. 7632
  12. 1300
  13. 875
  14. 1556
  15. 60
  16. 25392
  17. 53580
  18. 10604
  19. 31266
  20. 4
  21. 21250
  22. 18522
  23. 22880
  24. 3783
  25. 2125
  26. 59800
  27. 59
  28. 103125
  29. 3136
  30. 6090
  31. 4473
  32. 56520
  33. 1032
  34. 25925
  35. 508
  36. 2480
  37. 28750
  38. 1350
  39. 102
  40. 10648

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