Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
- 2.What amount will ₹15200 grow to in 1 year at 8% per year compound interest (in ₹)?
- 3.A scooter is worth ₹27000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 4.What amount will ₹58000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 5.Find the compound interest on ₹8900 at 10% per year for 2 years, compounded every year (in ₹).
- 6.What amount will ₹15600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 7.What amount will ₹19800 grow to in 1 year at 10% per year compound interest (in ₹)?
- 8.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 9.A scooter is worth ₹57700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
- 11.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 12.Find the compound interest on ₹14800 at 25% per year for 2 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
- 14.Find the compound interest on ₹28200 at 5% per year for 1 year, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹18400 at 25% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹52400 at 25% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹10200 at 10% per year for 2 years (in ₹)?
- 19.A town has 44500 people. The population grows by 20% every year. What will the population be after 3 years?
- 20.What is the difference between the compound interest and the simple interest on ₹5100 at 10% per year for 2 years (in ₹)?
- 21.Find the compound interest on ₹49400 at 20% per year for 2 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹8000 at 25% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹55000 at 10% per year for 3 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
- 26.A town has 14200 people. The population grows by 10% every year. What will the population be after 2 years?
- 27.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹56600 at 10% per year for 2 years (in ₹)?
- 29.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
- 30.What is the difference between the compound interest and the simple interest on ₹30000 at 15% per year for 2 years (in ₹)?
- 31.What amount will ₹42500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 32.What amount will ₹12800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹13600 at 25% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 36.A scooter is worth ₹14500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 37.A scooter is worth ₹17000. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 38.Find the compound interest on ₹50000 at 12% per year for 2 years, compounded every year (in ₹).
- 39.Find the compound interest on ₹30000 at 25% per year for 1 year, compounded every year (in ₹).
- 40.What is the difference between the compound interest and the simple interest on ₹38600 at 20% per year for 2 years (in ₹)?
Answer key
- 12167
- 16416
- 13824
- 77198
- 1869
- 17199
- 21780
- 69984
- 54815
- 24
- 12544
- 8325
- 28975
- 1410
- 720
- 1150
- 3275
- 102
- 76896
- 51
- 21736
- 500
- 6305
- 18205
- 2544
- 17182
- 352
- 566
- 27783
- 675
- 45968
- 16928
- 28
- 850
- 1261
- 13920
- 13600
- 12720
- 7500
- 1544
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