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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 447 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹39500 at 20% per year for 3 years, compounded every year (in ₹).
  4. 4.A town has 59200 people. The population grows by 5% every year. What will the population be after 2 years?
  5. 5.What amount will ₹53400 grow to in 2 years at 10% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹35200 at 15% per year for 2 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹18300 at 15% per year for 1 year, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹5000 at 20% per year for 3 years, compounded every year (in ₹).
  10. 10.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹9300 at 20% per year for 2 years (in ₹)?
  12. 12.What amount will ₹41200 grow to in 2 years at 25% per year compound interest (in ₹)?
  13. 13.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  14. 14.A scooter is worth ₹5900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  15. 15.Find the compound interest on ₹10400 at 25% per year for 2 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹5200 at 5% per year for 2 years, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹9600 at 25% per year for 2 years (in ₹)?
  18. 18.A town has 29400 people. The population grows by 8% every year. What will the population be after 1 year?
  19. 19.What amount will ₹59400 grow to in 1 year at 5% per year compound interest (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹58800 at 5% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹4800 at 15% per year for 2 years (in ₹)?
  22. 22.A town has 5400 people. The population grows by 12% every year. What will the population be after 1 year?
  23. 23.A town has 53900 people. The population grows by 5% every year. What will the population be after 1 year?
  24. 24.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
  25. 25.What amount will ₹19000 grow to in 3 years at 10% per year compound interest (in ₹)?
  26. 26.A town has 18000 people. The population grows by 10% every year. What will the population be after 3 years?
  27. 27.A town has 33900 people. The population grows by 8% every year. What will the population be after 1 year?
  28. 28.Find the compound interest on ₹14800 at 4% per year for 1 year, compounded every year (in ₹).
  29. 29.What amount will ₹14600 grow to in 1 year at 25% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
  31. 31.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
  32. 32.What amount will ₹36000 grow to in 2 years at 15% per year compound interest (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹8400 at 5% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹14300 at 20% per year for 2 years, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹39200 at 25% per year for 2 years, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹50400 at 8% per year for 1 year, compounded every year (in ₹).
  39. 39.What amount will ₹50000 grow to in 2 years at 25% per year compound interest (in ₹)?
  40. 40.A scooter is worth ₹24400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 2522
  2. 6305
  3. 28756
  4. 65268
  5. 64614
  6. 11352
  7. 5824
  8. 2745
  9. 3640
  10. 49572
  11. 372
  12. 64375
  13. 21600
  14. 5605
  15. 5850
  16. 533
  17. 600
  18. 31752
  19. 62370
  20. 147
  21. 108
  22. 6048
  23. 56595
  24. 84
  25. 25289
  26. 23958
  27. 36612
  28. 592
  29. 18250
  30. 48
  31. 64827
  32. 47610
  33. 21
  34. 7566
  35. 6292
  36. 9984
  37. 22050
  38. 4032
  39. 78125
  40. 17629

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