Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 448 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹30400 at 15% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
6. 6.What amount will ₹15800 grow to in 1 year at 20% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹44100 at 10% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹57600 at 25% per year for 1 year, compounded every year (in ₹).
11. 11.A scooter is worth ₹5700. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
12. 12.What amount will ₹37000 grow to in 1 year at 10% per year compound interest (in ₹)?
13. 13.A town has 45600 people. The population grows by 20% every year. What will the population be after 2 years?
14. 14.What is the difference between the compound interest and the simple interest on ₹12400 at 15% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹4400 at 5% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹21900 at 5% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹18000 at 10% per year for 1 year, compounded every year (in ₹).
18. 18.What amount will ₹2000 grow to in 3 years at 10% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
20. 20.A scooter is worth ₹45000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
21. 21.What amount will ₹26000 grow to in 1 year at 5% per year compound interest (in ₹)?
22. 22.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
23. 23.A scooter is worth ₹40600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
24. 24.A scooter is worth ₹22100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
25. 25.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹3300 at 10% per year for 2 years (in ₹)?
27. 27.What amount will ₹40800 grow to in 1 year at 10% per year compound interest (in ₹)?
28. 28.What amount will ₹15500 grow to in 2 years at 10% per year compound interest (in ₹)?
29. 29.A scooter is worth ₹59300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
30. 30.A scooter is worth ₹3200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹39600 at 15% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹30800 at 15% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹34900 grow to in 1 year at 8% per year compound interest (in ₹)?
34. 34.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
35. 35.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
36. 36.Find the compound interest on ₹34700 at 20% per year for 2 years, compounded every year (in ₹).
37. 37.What amount will ₹42500 grow to in 2 years at 12% per year compound interest (in ₹)?
38. 38.What amount will ₹14100 grow to in 1 year at 25% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹40000 at 25% per year for 3 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹4400 at 15% per year for 2 years, compounded every year (in ₹).

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