Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 449 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 29600 people. The population grows by 10% every year. What will the population be after 2 years?
2. 2.What amount will ₹18400 grow to in 2 years at 25% per year compound interest (in ₹)?
3. 3.What amount will ₹34800 grow to in 1 year at 5% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹44800 at 15% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹44000 at 10% per year for 3 years, compounded every year (in ₹).
6. 6.A scooter is worth ₹39600. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
7. 7.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
8. 8.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
9. 9.What is the difference between the compound interest and the simple interest on ₹56200 at 20% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹25200 at 5% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹27000 at 20% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹34300 at 25% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹19200 at 5% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹23700 at 10% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹26400 at 20% per year for 2 years (in ₹)?
19. 19.A town has 33200 people. The population grows by 15% every year. What will the population be after 2 years?
20. 20.What is the difference between the compound interest and the simple interest on ₹34600 at 20% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹24900 at 20% per year for 2 years, compounded every year (in ₹).
22. 22.What amount will ₹34900 grow to in 2 years at 10% per year compound interest (in ₹)?
23. 23.A scooter is worth ₹40000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
24. 24.A scooter is worth ₹54400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
25. 25.A scooter is worth ₹45400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
26. 26.What amount will ₹56100 grow to in 1 year at 5% per year compound interest (in ₹)?
27. 27.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
28. 28.What amount will ₹39600 grow to in 2 years at 20% per year compound interest (in ₹)?
29. 29.What amount will ₹23200 grow to in 2 years at 25% per year compound interest (in ₹)?
30. 30.A scooter is worth ₹56800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
31. 31.What amount will ₹42000 grow to in 3 years at 10% per year compound interest (in ₹)?
32. 32.A town has 50600 people. The population grows by 15% every year. What will the population be after 1 year?
33. 33.What is the difference between the compound interest and the simple interest on ₹45600 at 20% per year for 2 years (in ₹)?
34. 34.What amount will ₹37500 grow to in 2 years at 4% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹56800 at 15% per year for 2 years (in ₹)?
36. 36.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹38600 at 5% per year for 1 year, compounded every year (in ₹).
38. 38.Find the compound interest on ₹22400 at 5% per year for 2 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹20800 at 5% per year for 2 years, compounded every year (in ₹).
40. 40.A town has 6400 people. The population grows by 8% every year. What will the population be after 1 year?

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