Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 2.A town has 31900 people. The population grows by 10% every year. What will the population be after 2 years?
- 3.A scooter is worth ₹46500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 4.What amount will ₹13000 grow to in 1 year at 12% per year compound interest (in ₹)?
- 5.What amount will ₹58800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 7.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹15100 at 10% per year for 2 years, compounded every year (in ₹).
- 9.What amount will ₹12000 grow to in 1 year at 20% per year compound interest (in ₹)?
- 10.A town has 20000 people. The population grows by 10% every year. What will the population be after 3 years?
- 11.A scooter is worth ₹21000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 12.Find the compound interest on ₹40500 at 10% per year for 2 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹11100 at 20% per year for 2 years, compounded every year (in ₹).
- 14.A scooter is worth ₹47200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 15.What amount will ₹35500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹4000 at 5% per year for 2 years (in ₹)?
- 18.What amount will ₹35400 grow to in 2 years at 20% per year compound interest (in ₹)?
- 19.A town has 59600 people. The population grows by 25% every year. What will the population be after 2 years?
- 20.A scooter is worth ₹6000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 21.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 22.A town has 6500 people. The population grows by 8% every year. What will the population be after 1 year?
- 23.A town has 52000 people. The population grows by 5% every year. What will the population be after 2 years?
- 24.A town has 21600 people. The population grows by 12% every year. What will the population be after 1 year?
- 25.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹21600 at 10% per year for 1 year, compounded every year (in ₹).
- 28.What amount will ₹19600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹9000 at 10% per year for 3 years, compounded every year (in ₹).
- 30.A town has 24800 people. The population grows by 10% every year. What will the population be after 1 year?
- 31.What is the difference between the compound interest and the simple interest on ₹48400 at 25% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹22000 at 20% per year for 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹51900 at 20% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹22500 at 8% per year for 2 years, compounded every year (in ₹).
- 35.A town has 22500 people. The population grows by 12% every year. What will the population be after 2 years?
- 36.A scooter is worth ₹33600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 37.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 38.A town has 10000 people. The population grows by 10% every year. What will the population be after 1 year?
- 39.What is the difference between the compound interest and the simple interest on ₹12000 at 15% per year for 2 years (in ₹)?
- 40.Find the compound interest on ₹43000 at 20% per year for 3 years, compounded every year (in ₹).
Answer key
- 4913
- 38599
- 37665
- 14560
- 64827
- 48
- 37044
- 3171
- 14400
- 26620
- 20160
- 8505
- 4884
- 34102
- 61344
- 12
- 10
- 50976
- 93125
- 4374
- 416
- 7020
- 57330
- 24192
- 720
- 324
- 2160
- 25921
- 2979
- 27280
- 3025
- 880
- 2076
- 3744
- 28224
- 14175
- 80
- 11000
- 270
- 31304
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