← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 464 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  2. 2.A town has 10000 people. The population grows by 5% every year. What will the population be after 1 year?
  3. 3.What amount will ₹26000 grow to in 1 year at 8% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹25800 at 10% per year for 2 years (in ₹)?
  5. 5.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹30500 at 15% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹52100 at 20% per year for 2 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹52800 at 5% per year for 2 years (in ₹)?
  9. 9.What amount will ₹42500 grow to in 2 years at 12% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹34000 at 5% per year for 2 years (in ₹)?
  11. 11.What amount will ₹28400 grow to in 2 years at 15% per year compound interest (in ₹)?
  12. 12.A town has 26000 people. The population grows by 5% every year. What will the population be after 2 years?
  13. 13.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
  14. 14.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  15. 15.A town has 54400 people. The population grows by 25% every year. What will the population be after 3 years?
  16. 16.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹5700 at 25% per year for 1 year, compounded every year (in ₹).
  18. 18.A scooter is worth ₹14000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  19. 19.Find the compound interest on ₹9900 at 5% per year for 1 year, compounded every year (in ₹).
  20. 20.What amount will ₹2500 grow to in 2 years at 12% per year compound interest (in ₹)?
  21. 21.A town has 59000 people. The population grows by 4% every year. What will the population be after 1 year?
  22. 22.Find the compound interest on ₹9500 at 8% per year for 1 year, compounded every year (in ₹).
  23. 23.What amount will ₹22600 grow to in 1 year at 12% per year compound interest (in ₹)?
  24. 24.What amount will ₹4000 grow to in 3 years at 20% per year compound interest (in ₹)?
  25. 25.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  26. 26.What amount will ₹17900 grow to in 1 year at 20% per year compound interest (in ₹)?
  27. 27.What amount will ₹53200 grow to in 1 year at 10% per year compound interest (in ₹)?
  28. 28.What amount will ₹14200 grow to in 1 year at 15% per year compound interest (in ₹)?
  29. 29.A town has 19200 people. The population grows by 15% every year. What will the population be after 2 years?
  30. 30.What amount will ₹43300 grow to in 1 year at 20% per year compound interest (in ₹)?
  31. 31.A scooter is worth ₹31000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  32. 32.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹24800 at 20% per year for 2 years (in ₹)?
  34. 34.What amount will ₹11900 grow to in 1 year at 25% per year compound interest (in ₹)?
  35. 35.What amount will ₹39000 grow to in 3 years at 10% per year compound interest (in ₹)?
  36. 36.A town has 14400 people. The population grows by 4% every year. What will the population be after 1 year?
  37. 37.What is the difference between the compound interest and the simple interest on ₹50200 at 20% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹29600 at 10% per year for 1 year, compounded every year (in ₹).
  39. 39.What amount will ₹6000 grow to in 3 years at 10% per year compound interest (in ₹)?
  40. 40.What amount will ₹19000 grow to in 3 years at 10% per year compound interest (in ₹)?

Answer key

  1. 180
  2. 10500
  3. 28080
  4. 258
  5. 43740
  6. 4575
  7. 22924
  8. 132
  9. 53312
  10. 85
  11. 37559
  12. 28665
  13. 40
  14. 13718
  15. 106250
  16. 10675
  17. 1425
  18. 13300
  19. 495
  20. 3136
  21. 61360
  22. 760
  23. 25312
  24. 6912
  25. 48668
  26. 21480
  27. 58520
  28. 16330
  29. 25392
  30. 51960
  31. 22599
  32. 15264
  33. 992
  34. 14875
  35. 51909
  36. 14976
  37. 2008
  38. 2960
  39. 7986
  40. 25289

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets