Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 465 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹5800 at 10% per year for 2 years (in ₹)?
2. 2.What amount will ₹57400 grow to in 1 year at 4% per year compound interest (in ₹)?
3. 3.What amount will ₹46400 grow to in 1 year at 4% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹14000 at 15% per year for 2 years (in ₹)?
6. 6.A town has 27300 people. The population grows by 12% every year. What will the population be after 1 year?
7. 7.A scooter is worth ₹21200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
8. 8.A town has 41600 people. The population grows by 25% every year. What will the population be after 3 years?
9. 9.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
10. 10.What amount will ₹31400 grow to in 1 year at 12% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹55900 at 20% per year for 1 year, compounded every year (in ₹).
12. 12.Find the compound interest on ₹35300 at 12% per year for 1 year, compounded every year (in ₹).
13. 13.A scooter is worth ₹6400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹45600 at 5% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹34400 at 25% per year for 2 years (in ₹)?
17. 17.A town has 2200 people. The population grows by 20% every year. What will the population be after 1 year?
18. 18.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
19. 19.A town has 24300 people. The population grows by 5% every year. What will the population be after 1 year?
20. 20.A town has 10000 people. The population grows by 12% every year. What will the population be after 2 years?
21. 21.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
23. 23.What amount will ₹26400 grow to in 1 year at 12% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹34000 at 25% per year for 2 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹47100 at 4% per year for 1 year, compounded every year (in ₹).
27. 27.A town has 57300 people. The population grows by 5% every year. What will the population be after 1 year?
28. 28.A scooter is worth ₹23400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
29. 29.What amount will ₹41000 grow to in 1 year at 20% per year compound interest (in ₹)?
30. 30.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
31. 31.Find the compound interest on ₹46000 at 25% per year for 2 years, compounded every year (in ₹).
32. 32.What amount will ₹22000 grow to in 1 year at 8% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹11600 at 5% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹21500 at 10% per year for 2 years, compounded every year (in ₹).
35. 35.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
36. 36.A town has 18600 people. The population grows by 10% every year. What will the population be after 1 year?
37. 37.What is the difference between the compound interest and the simple interest on ₹8300 at 10% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹51400 at 5% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹5200 at 15% per year for 2 years (in ₹)?

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