Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹32300 at 20% per year for 2 years (in ₹)?
- 3.What amount will ₹48000 grow to in 1 year at 12% per year compound interest (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹46000 at 25% per year for 2 years (in ₹)?
- 5.What amount will ₹28100 grow to in 2 years at 20% per year compound interest (in ₹)?
- 6.A town has 55200 people. The population grows by 25% every year. What will the population be after 2 years?
- 7.Find the compound interest on ₹11000 at 20% per year for 1 year, compounded every year (in ₹).
- 8.Find the compound interest on ₹23000 at 10% per year for 3 years, compounded every year (in ₹).
- 9.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 10.What amount will ₹54200 grow to in 1 year at 25% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹46600 at 10% per year for 2 years, compounded every year (in ₹).
- 12.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 13.What amount will ₹13900 grow to in 1 year at 15% per year compound interest (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
- 15.What amount will ₹33100 grow to in 1 year at 25% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹24100 at 20% per year for 2 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹41300 at 5% per year for 1 year, compounded every year (in ₹).
- 18.A scooter is worth ₹10000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹51700 at 10% per year for 2 years (in ₹)?
- 20.What amount will ₹42000 grow to in 1 year at 20% per year compound interest (in ₹)?
- 21.Find the compound interest on ₹18700 at 10% per year for 1 year, compounded every year (in ₹).
- 22.A town has 26800 people. The population grows by 15% every year. What will the population be after 2 years?
- 23.A scooter is worth ₹3100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 24.Find the compound interest on ₹7200 at 5% per year for 2 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹7300 at 20% per year for 1 year, compounded every year (in ₹).
- 26.A scooter is worth ₹45000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 27.A scooter is worth ₹39300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 28.What amount will ₹29700 grow to in 1 year at 8% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
- 30.A town has 16800 people. The population grows by 15% every year. What will the population be after 1 year?
- 31.A scooter is worth ₹51400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 32.What amount will ₹42500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹38400 at 5% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 35.Find the compound interest on ₹46800 at 5% per year for 2 years, compounded every year (in ₹).
- 36.What is the difference between the compound interest and the simple interest on ₹38800 at 20% per year for 2 years (in ₹)?
- 37.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
- 38.What is the difference between the compound interest and the simple interest on ₹13200 at 5% per year for 2 years (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹11400 at 10% per year for 2 years (in ₹)?
- 40.Find the compound interest on ₹9100 at 8% per year for 1 year, compounded every year (in ₹).
Answer key
- 208
- 1292
- 53760
- 2875
- 40464
- 86250
- 2200
- 7613
- 5044
- 67750
- 9786
- 48013
- 15985
- 684
- 41375
- 10604
- 2065
- 9216
- 517
- 50400
- 1870
- 35443
- 2480
- 738
- 1460
- 41472
- 33405
- 32076
- 7904
- 19320
- 48830
- 45968
- 96
- 1261
- 4797
- 1552
- 43904
- 33
- 114
- 728
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