Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 477 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹43800 at 20% per year for 2 years (in ₹)?
2. 2.A town has 39600 people. The population grows by 15% every year. What will the population be after 2 years?
3. 3.What is the difference between the compound interest and the simple interest on ₹21200 at 25% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹49500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
5. 5.A town has 46500 people. The population grows by 10% every year. What will the population be after 1 year?
6. 6.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹52500 at 10% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
9. 9.Find the compound interest on ₹34400 at 5% per year for 2 years, compounded every year (in ₹).
10. 10.A town has 24800 people. The population grows by 5% every year. What will the population be after 2 years?
11. 11.What amount will ₹48800 grow to in 2 years at 15% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹8800 at 25% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹45600 at 25% per year for 2 years (in ₹)?
14. 14.A town has 47400 people. The population grows by 20% every year. What will the population be after 1 year?
15. 15.A town has 44000 people. The population grows by 4% every year. What will the population be after 1 year?
16. 16.A town has 34700 people. The population grows by 10% every year. What will the population be after 2 years?
17. 17.What is the difference between the compound interest and the simple interest on ₹8400 at 25% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
19. 19.Find the compound interest on ₹37900 at 15% per year for 1 year, compounded every year (in ₹).
20. 20.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
21. 21.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
22. 22.A town has 28900 people. The population grows by 4% every year. What will the population be after 1 year?
23. 23.A scooter is worth ₹13200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹29600 at 20% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹48600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
26. 26.What amount will ₹17100 grow to in 1 year at 20% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹13800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
28. 28.A scooter is worth ₹38700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
29. 29.Find the compound interest on ₹5400 at 10% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹40400 at 25% per year for 2 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹51900 at 10% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹17200 at 20% per year for 2 years (in ₹)?
34. 34.What amount will ₹18200 grow to in 1 year at 15% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹4200 at 10% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
37. 37.A town has 27800 people. The population grows by 5% every year. What will the population be after 1 year?
38. 38.A scooter is worth ₹45400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹19200 at 5% per year for 2 years (in ₹)?
40. 40.What amount will ₹22500 grow to in 3 years at 20% per year compound interest (in ₹)?

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