Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹23300. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹7200 at 25% per year for 2 years (in ₹)?
- 3.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 4.A town has 26600 people. The population grows by 8% every year. What will the population be after 1 year?
- 5.What amount will ₹58600 grow to in 1 year at 15% per year compound interest (in ₹)?
- 6.A town has 28000 people. The population grows by 5% every year. What will the population be after 2 years?
- 7.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 8.A town has 26800 people. The population grows by 5% every year. What will the population be after 2 years?
- 9.What is the difference between the compound interest and the simple interest on ₹56200 at 10% per year for 2 years (in ₹)?
- 10.A town has 37200 people. The population grows by 20% every year. What will the population be after 1 year?
- 11.What is the difference between the compound interest and the simple interest on ₹12400 at 5% per year for 2 years (in ₹)?
- 12.What amount will ₹57500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 13.A scooter is worth ₹8000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 14.Find the compound interest on ₹22000 at 8% per year for 1 year, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹54700 at 10% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
- 17.A town has 50900 people. The population grows by 4% every year. What will the population be after 1 year?
- 18.What amount will ₹19000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 19.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 20.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹41600 at 5% per year for 2 years (in ₹)?
- 22.Find the compound interest on ₹37600 at 25% per year for 2 years, compounded every year (in ₹).
- 23.What is the difference between the compound interest and the simple interest on ₹13200 at 15% per year for 2 years (in ₹)?
- 24.A town has 35000 people. The population grows by 8% every year. What will the population be after 2 years?
- 25.What is the difference between the compound interest and the simple interest on ₹25200 at 20% per year for 2 years (in ₹)?
- 26.What amount will ₹4400 grow to in 1 year at 8% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
- 28.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
- 29.A town has 24700 people. The population grows by 15% every year. What will the population be after 1 year?
- 30.What amount will ₹56400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹10400 at 25% per year for 2 years (in ₹)?
- 32.What amount will ₹54700 grow to in 1 year at 20% per year compound interest (in ₹)?
- 33.What amount will ₹28000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 34.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 35.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
- 36.What amount will ₹22400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
- 38.A town has 16000 people. The population grows by 20% every year. What will the population be after 3 years?
- 39.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
- 40.What amount will ₹18000 grow to in 2 years at 25% per year compound interest (in ₹)?
Answer key
- 18640
- 450
- 9261
- 28728
- 67390
- 30870
- 2522
- 29547
- 562
- 44640
- 31
- 72128
- 4096
- 1760
- 547
- 8736
- 52936
- 32832
- 75264
- 29160
- 104
- 21150
- 297
- 40824
- 1008
- 4752
- 832
- 144
- 28405
- 62181
- 650
- 65640
- 37268
- 18522
- 43904
- 35000
- 5824
- 27648
- 40
- 28125
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets