← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 49 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹45200 at 15% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹34200 at 10% per year for 2 years, compounded every year (in ₹).
  3. 3.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹55600 at 5% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹28000 at 25% per year for 2 years, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹31500 at 20% per year for 2 years, compounded every year (in ₹).
  7. 7.What amount will ₹7400 grow to in 1 year at 25% per year compound interest (in ₹)?
  8. 8.Find the compound interest on ₹18900 at 25% per year for 1 year, compounded every year (in ₹).
  9. 9.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
  10. 10.What is the difference between the compound interest and the simple interest on ₹2800 at 25% per year for 2 years (in ₹)?
  11. 11.What amount will ₹3400 grow to in 2 years at 20% per year compound interest (in ₹)?
  12. 12.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
  13. 13.What amount will ₹59600 grow to in 2 years at 5% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  15. 15.A scooter is worth ₹18400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  16. 16.A scooter is worth ₹54000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  17. 17.What amount will ₹6400 grow to in 3 years at 25% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹29700 at 20% per year for 2 years, compounded every year (in ₹).
  19. 19.What amount will ₹10600 grow to in 1 year at 25% per year compound interest (in ₹)?
  20. 20.What amount will ₹16000 grow to in 2 years at 15% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹53600 at 25% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹51900 at 10% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹25600 at 15% per year for 2 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹34400 at 15% per year for 2 years, compounded every year (in ₹).
  25. 25.What amount will ₹33300 grow to in 1 year at 5% per year compound interest (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹32500 at 10% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹37500 at 8% per year for 2 years, compounded every year (in ₹).
  28. 28.A town has 16000 people. The population grows by 10% every year. What will the population be after 1 year?
  29. 29.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹29300 at 25% per year for 1 year, compounded every year (in ₹).
  32. 32.A scooter is worth ₹10100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹36300 at 10% per year for 2 years (in ₹)?
  34. 34.A scooter is worth ₹24600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  35. 35.What amount will ₹44400 grow to in 1 year at 10% per year compound interest (in ₹)?
  36. 36.A town has 45500 people. The population grows by 10% every year. What will the population be after 1 year?
  37. 37.What amount will ₹24500 grow to in 3 years at 20% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹17200 at 5% per year for 2 years, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹20800 at 25% per year for 2 years (in ₹)?
  40. 40.Find the compound interest on ₹50800 at 15% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 1017
  2. 7182
  3. 37044
  4. 139
  5. 15750
  6. 13860
  7. 9250
  8. 4725
  9. 72128
  10. 175
  11. 4896
  12. 15680
  13. 65709
  14. 3783
  15. 16606
  16. 51840
  17. 12500
  18. 13068
  19. 13250
  20. 21160
  21. 3350
  22. 519
  23. 8256
  24. 11094
  25. 34965
  26. 325
  27. 6240
  28. 17600
  29. 12501
  30. 13356
  31. 7325
  32. 9090
  33. 363
  34. 19926
  35. 48840
  36. 50050
  37. 42336
  38. 1763
  39. 1300
  40. 16383

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets