Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 483 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
2. 2.A town has 59600 people. The population grows by 20% every year. What will the population be after 1 year?
3. 3.A town has 23200 people. The population grows by 5% every year. What will the population be after 1 year?
4. 4.A town has 50800 people. The population grows by 15% every year. What will the population be after 1 year?
5. 5.A scooter is worth ₹33600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
6. 6.A scooter is worth ₹21700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
7. 7.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
8. 8.A scooter is worth ₹10500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
9. 9.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹56600 at 10% per year for 1 year, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹54800 at 15% per year for 2 years (in ₹)?
12. 12.What amount will ₹33600 grow to in 3 years at 25% per year compound interest (in ₹)?
13. 13.A scooter is worth ₹42500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹19400 at 20% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹20000 at 15% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹42300 at 25% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹15600 at 15% per year for 2 years, compounded every year (in ₹).
18. 18.A scooter is worth ₹31400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
19. 19.Find the compound interest on ₹23000 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.What amount will ₹20800 grow to in 2 years at 25% per year compound interest (in ₹)?
21. 21.What amount will ₹57500 grow to in 1 year at 5% per year compound interest (in ₹)?
22. 22.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹13400 at 10% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹8500 grow to in 2 years at 10% per year compound interest (in ₹)?
25. 25.What amount will ₹31200 grow to in 2 years at 15% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹58000 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.A scooter is worth ₹6000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹28000 at 15% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹15700 at 20% per year for 2 years, compounded every year (in ₹).
30. 30.Find the compound interest on ₹6000 at 25% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹32400 grow to in 1 year at 5% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
33. 33.What amount will ₹41600 grow to in 3 years at 25% per year compound interest (in ₹)?
34. 34.A town has 49900 people. The population grows by 10% every year. What will the population be after 1 year?
35. 35.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹31500 at 20% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 36900 people. The population grows by 20% every year. What will the population be after 2 years?
38. 38.Find the compound interest on ₹8000 at 25% per year for 2 years, compounded every year (in ₹).
39. 39.A town has 10400 people. The population grows by 10% every year. What will the population be after 2 years?
40. 40.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).

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