Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 489 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹6300 grow to in 1 year at 12% per year compound interest (in ₹)?
2. 2.A scooter is worth ₹12800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
3. 3.Find the compound interest on ₹12800 at 25% per year for 3 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹14000 at 10% per year for 2 years (in ₹)?
6. 6.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹39600 at 15% per year for 2 years (in ₹)?
8. 8.A town has 44400 people. The population grows by 10% every year. What will the population be after 1 year?
9. 9.Find the compound interest on ₹22000 at 10% per year for 3 years, compounded every year (in ₹).
10. 10.A town has 48200 people. The population grows by 10% every year. What will the population be after 1 year?
11. 11.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
12. 12.What amount will ₹25000 grow to in 2 years at 4% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹42400 at 10% per year for 2 years (in ₹)?
14. 14.A town has 50000 people. The population grows by 12% every year. What will the population be after 2 years?
15. 15.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
16. 16.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹19600 at 20% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹5200 at 25% per year for 2 years (in ₹)?
19. 19.What amount will ₹55600 grow to in 1 year at 10% per year compound interest (in ₹)?
20. 20.A town has 14400 people. The population grows by 4% every year. What will the population be after 1 year?
21. 21.Find the compound interest on ₹18400 at 25% per year for 2 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹11200 at 15% per year for 2 years (in ₹)?
23. 23.A town has 37900 people. The population grows by 10% every year. What will the population be after 1 year?
24. 24.What is the difference between the compound interest and the simple interest on ₹30300 at 20% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
26. 26.What amount will ₹7000 grow to in 1 year at 4% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹29300 at 10% per year for 1 year, compounded every year (in ₹).
28. 28.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
29. 29.What amount will ₹41100 grow to in 2 years at 10% per year compound interest (in ₹)?
30. 30.A town has 12500 people. The population grows by 12% every year. What will the population be after 2 years?
31. 31.Find the compound interest on ₹46900 at 20% per year for 2 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹12800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
35. 35.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
36. 36.A town has 54000 people. The population grows by 15% every year. What will the population be after 2 years?
37. 37.A scooter is worth ₹18400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹25700 at 20% per year for 2 years (in ₹)?
39. 39.What amount will ₹40800 grow to in 1 year at 5% per year compound interest (in ₹)?
40. 40.A scooter is worth ₹56600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?

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