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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 497 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹49500 at 10% per year for 2 years (in ₹)?
  2. 2.A town has 41600 people. The population grows by 25% every year. What will the population be after 3 years?
  3. 3.What amount will ₹53200 grow to in 2 years at 25% per year compound interest (in ₹)?
  4. 4.What amount will ₹13600 grow to in 1 year at 5% per year compound interest (in ₹)?
  5. 5.A town has 20000 people. The population grows by 15% every year. What will the population be after 1 year?
  6. 6.What amount will ₹16200 grow to in 1 year at 5% per year compound interest (in ₹)?
  7. 7.A scooter is worth ₹30000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹45400 at 20% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹56800 at 5% per year for 2 years (in ₹)?
  10. 10.What amount will ₹42400 grow to in 2 years at 25% per year compound interest (in ₹)?
  11. 11.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
  12. 12.Find the compound interest on ₹56500 at 10% per year for 2 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹21500 at 10% per year for 1 year, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹22000 at 10% per year for 2 years (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹14000 at 25% per year for 2 years (in ₹)?
  16. 16.What amount will ₹13400 grow to in 1 year at 10% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹28100 at 20% per year for 2 years (in ₹)?
  19. 19.A scooter is worth ₹4000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  20. 20.Find the compound interest on ₹55700 at 4% per year for 1 year, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹31200 at 10% per year for 1 year, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹29200 at 25% per year for 2 years, compounded every year (in ₹).
  23. 23.A town has 36300 people. The population grows by 8% every year. What will the population be after 1 year?
  24. 24.Find the compound interest on ₹28800 at 15% per year for 2 years, compounded every year (in ₹).
  25. 25.A town has 29000 people. The population grows by 10% every year. What will the population be after 1 year?
  26. 26.Find the compound interest on ₹3600 at 15% per year for 2 years, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
  28. 28.A town has 7200 people. The population grows by 8% every year. What will the population be after 1 year?
  29. 29.A town has 3700 people. The population grows by 4% every year. What will the population be after 1 year?
  30. 30.What is the difference between the compound interest and the simple interest on ₹53400 at 10% per year for 2 years (in ₹)?
  31. 31.A scooter is worth ₹60000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  32. 32.Find the compound interest on ₹18000 at 20% per year for 3 years, compounded every year (in ₹).
  33. 33.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  34. 34.A scooter is worth ₹18600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  35. 35.Find the compound interest on ₹47900 at 10% per year for 2 years, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹2800 at 5% per year for 2 years (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹29200 at 15% per year for 2 years (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹38400 at 5% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹2600 at 10% per year for 1 year, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹58000 at 5% per year for 2 years (in ₹)?

Answer key

  1. 495
  2. 81250
  3. 83125
  4. 14280
  5. 23000
  6. 17010
  7. 16875
  8. 1816
  9. 142
  10. 66250
  11. 59584
  12. 11865
  13. 2150
  14. 220
  15. 875
  16. 14740
  17. 8827
  18. 1124
  19. 2890
  20. 2228
  21. 3120
  22. 16425
  23. 39204
  24. 9288
  25. 31900
  26. 1161
  27. 20835
  28. 7776
  29. 3848
  30. 534
  31. 46464
  32. 13104
  33. 34295
  34. 17112
  35. 10059
  36. 7
  37. 657
  38. 96
  39. 260
  40. 145

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