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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 498 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹3200 grow to in 3 years at 25% per year compound interest (in ₹)?
  2. 2.What amount will ₹32900 grow to in 1 year at 4% per year compound interest (in ₹)?
  3. 3.What amount will ₹51600 grow to in 2 years at 15% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹29500 at 20% per year for 2 years (in ₹)?
  5. 5.What amount will ₹26800 grow to in 2 years at 15% per year compound interest (in ₹)?
  6. 6.What amount will ₹10000 grow to in 2 years at 25% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹50400 at 5% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹14000 at 5% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹8300 at 20% per year for 1 year, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
  12. 12.What amount will ₹5800 grow to in 1 year at 20% per year compound interest (in ₹)?
  13. 13.A scooter is worth ₹13900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  14. 14.What amount will ₹18100 grow to in 1 year at 4% per year compound interest (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
  16. 16.A scooter is worth ₹47500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  17. 17.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
  18. 18.A town has 32000 people. The population grows by 25% every year. What will the population be after 3 years?
  19. 19.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  20. 20.A town has 37600 people. The population grows by 15% every year. What will the population be after 2 years?
  21. 21.What is the difference between the compound interest and the simple interest on ₹10800 at 5% per year for 2 years (in ₹)?
  22. 22.What amount will ₹37500 grow to in 1 year at 15% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹3900 at 10% per year for 1 year, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹8700 at 10% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹49000 at 10% per year for 2 years (in ₹)?
  26. 26.What amount will ₹22900 grow to in 1 year at 5% per year compound interest (in ₹)?
  27. 27.A scooter is worth ₹30100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  28. 28.Find the compound interest on ₹22200 at 12% per year for 1 year, compounded every year (in ₹).
  29. 29.A town has 28400 people. The population grows by 25% every year. What will the population be after 1 year?
  30. 30.A scooter is worth ₹49000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  31. 31.A town has 58800 people. The population grows by 10% every year. What will the population be after 2 years?
  32. 32.Find the compound interest on ₹25600 at 5% per year for 2 years, compounded every year (in ₹).
  33. 33.What amount will ₹26900 grow to in 1 year at 5% per year compound interest (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
  36. 36.A scooter is worth ₹37400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  37. 37.A scooter is worth ₹44500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  38. 38.Find the compound interest on ₹46500 at 20% per year for 3 years, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹45200 at 5% per year for 2 years (in ₹)?
  40. 40.What amount will ₹12000 grow to in 1 year at 25% per year compound interest (in ₹)?

Answer key

  1. 6250
  2. 34216
  3. 68241
  4. 1180
  5. 35443
  6. 15625
  7. 126
  8. 21350
  9. 35
  10. 1660
  11. 4452
  12. 6960
  13. 10425
  14. 18824
  15. 56
  16. 43776
  17. 9150
  18. 62500
  19. 46305
  20. 49726
  21. 27
  22. 43125
  23. 390
  24. 87
  25. 490
  26. 24045
  27. 28896
  28. 2664
  29. 35500
  30. 35721
  31. 71148
  32. 2624
  33. 28245
  34. 272
  35. 1250
  36. 35530
  37. 40050
  38. 33852
  39. 113
  40. 15000

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