Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹16200 grow to in 1 year at 12% per year compound interest (in ₹)?
- 2.Find the compound interest on ₹14400 at 20% per year for 2 years, compounded every year (in ₹).
- 3.Find the compound interest on ₹3500 at 10% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
- 5.Find the compound interest on ₹46500 at 20% per year for 3 years, compounded every year (in ₹).
- 6.What amount will ₹49200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹18400 at 5% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹29300 at 10% per year for 2 years (in ₹)?
- 10.What amount will ₹36400 grow to in 2 years at 10% per year compound interest (in ₹)?
- 11.A scooter is worth ₹26000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 12.Find the compound interest on ₹37000 at 20% per year for 3 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 14.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 15.A town has 12500 people. The population grows by 8% every year. What will the population be after 2 years?
- 16.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹10700 at 20% per year for 2 years, compounded every year (in ₹).
- 18.Find the compound interest on ₹3800 at 8% per year for 1 year, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
- 20.A town has 23000 people. The population grows by 20% every year. What will the population be after 2 years?
- 21.Find the compound interest on ₹3000 at 20% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹5200 at 20% per year for 2 years (in ₹)?
- 23.A town has 25000 people. The population grows by 12% every year. What will the population be after 1 year?
- 24.A town has 22000 people. The population grows by 25% every year. What will the population be after 2 years?
- 25.Find the compound interest on ₹28000 at 5% per year for 2 years, compounded every year (in ₹).
- 26.What amount will ₹7200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 27.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹41600 at 25% per year for 2 years (in ₹)?
- 29.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 30.What amount will ₹43400 grow to in 1 year at 5% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹19000 at 20% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹9100 at 10% per year for 2 years, compounded every year (in ₹).
- 33.What amount will ₹27200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 34.Find the compound interest on ₹2100 at 20% per year for 1 year, compounded every year (in ₹).
- 35.What amount will ₹48000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹37600 at 25% per year for 1 year, compounded every year (in ₹).
- 37.A scooter is worth ₹25700. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 38.Find the compound interest on ₹40000 at 25% per year for 3 years, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹50400 at 25% per year for 2 years (in ₹)?
- 40.What amount will ₹9200 grow to in 2 years at 5% per year compound interest (in ₹)?
Answer key
- 18144
- 6336
- 350
- 29169
- 33852
- 54243
- 46
- 576
- 293
- 44044
- 14625
- 26936
- 12501
- 4913
- 14580
- 8827
- 4708
- 304
- 56
- 33120
- 600
- 208
- 28000
- 34375
- 2870
- 7938
- 75264
- 2600
- 5044
- 45570
- 760
- 1911
- 53125
- 420
- 63480
- 9400
- 20560
- 38125
- 3150
- 10143
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