Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 502 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹55900 grow to in 1 year at 12% per year compound interest (in ₹)?
2. 2.What amount will ₹30800 grow to in 1 year at 4% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹2300 at 25% per year for 1 year, compounded every year (in ₹).
4. 4.A town has 47900 people. The population grows by 4% every year. What will the population be after 1 year?
5. 5.What is the difference between the compound interest and the simple interest on ₹42900 at 10% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
7. 7.What amount will ₹30400 grow to in 3 years at 25% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
9. 9.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
10. 10.What amount will ₹22000 grow to in 3 years at 20% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹17700 at 12% per year for 1 year, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
13. 13.A scooter is worth ₹19000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
14. 14.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
15. 15.A town has 16900 people. The population grows by 10% every year. What will the population be after 2 years?
16. 16.What is the difference between the compound interest and the simple interest on ₹19600 at 25% per year for 2 years (in ₹)?
17. 17.A town has 10200 people. The population grows by 8% every year. What will the population be after 1 year?
18. 18.What amount will ₹29700 grow to in 1 year at 15% per year compound interest (in ₹)?
19. 19.A town has 45200 people. The population grows by 12% every year. What will the population be after 1 year?
20. 20.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
21. 21.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹23400 at 20% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹6800 at 5% per year for 2 years (in ₹)?
25. 25.What amount will ₹11300 grow to in 1 year at 10% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹45500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.What amount will ₹36600 grow to in 1 year at 15% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹49800 at 20% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹35900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
30. 30.What amount will ₹30600 grow to in 1 year at 4% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹18000 at 15% per year for 2 years, compounded every year (in ₹).
32. 32.A town has 57600 people. The population grows by 5% every year. What will the population be after 2 years?
33. 33.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
34. 34.A scooter is worth ₹24600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
35. 35.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹31200 grow to in 2 years at 5% per year compound interest (in ₹)?
37. 37.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
38. 38.What amount will ₹39100 grow to in 1 year at 25% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).

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