Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 508 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹35000 at 20% per year for 3 years, compounded every year (in ₹).
2. 2.What amount will ₹35100 grow to in 1 year at 15% per year compound interest (in ₹)?
3. 3.A town has 16000 people. The population grows by 25% every year. What will the population be after 3 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹35400 at 20% per year for 2 years (in ₹)?
5. 5.What amount will ₹55100 grow to in 1 year at 25% per year compound interest (in ₹)?
6. 6.What amount will ₹57400 grow to in 1 year at 5% per year compound interest (in ₹)?
7. 7.What amount will ₹3100 grow to in 2 years at 10% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹5700 at 8% per year for 1 year, compounded every year (in ₹).
9. 9.Find the compound interest on ₹46400 at 15% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹18900 at 5% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹19500 at 20% per year for 1 year, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹39600 at 15% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹46400 at 20% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹55600 at 12% per year for 1 year, compounded every year (in ₹).
15. 15.What amount will ₹28400 grow to in 2 years at 5% per year compound interest (in ₹)?
16. 16.A scooter is worth ₹42000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
17. 17.What amount will ₹14000 grow to in 3 years at 10% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹14000 at 5% per year for 2 years (in ₹)?
19. 19.What amount will ₹52000 grow to in 3 years at 20% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹37500 at 8% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹17000 grow to in 3 years at 10% per year compound interest (in ₹)?
22. 22.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
23. 23.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹33300 at 12% per year for 1 year, compounded every year (in ₹).
26. 26.A town has 54400 people. The population grows by 25% every year. What will the population be after 2 years?
27. 27.A town has 40000 people. The population grows by 4% every year. What will the population be after 2 years?
28. 28.Find the compound interest on ₹36400 at 8% per year for 1 year, compounded every year (in ₹).
29. 29.Find the compound interest on ₹16000 at 4% per year for 1 year, compounded every year (in ₹).
30. 30.A town has 48200 people. The population grows by 4% every year. What will the population be after 1 year?
31. 31.What amount will ₹21600 grow to in 2 years at 5% per year compound interest (in ₹)?
32. 32.What amount will ₹13100 grow to in 1 year at 10% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹46000 at 15% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹51000 at 10% per year for 2 years (in ₹)?
36. 36.A town has 12800 people. The population grows by 25% every year. What will the population be after 1 year?
37. 37.A scooter is worth ₹38600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
39. 39.A town has 22500 people. The population grows by 8% every year. What will the population be after 2 years?
40. 40.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).

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