Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 511 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹49600 grow to in 1 year at 4% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹47600 at 10% per year for 2 years (in ₹)?
3. 3.What amount will ₹4800 grow to in 3 years at 25% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹24800 at 20% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹44700 at 20% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
9. 9.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹16800 at 15% per year for 2 years (in ₹)?
11. 11.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
12. 12.A scooter is worth ₹25000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
13. 13.Find the compound interest on ₹45700 at 12% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹13600 at 10% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹33000 at 10% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹33600 at 5% per year for 2 years (in ₹)?
17. 17.A town has 20400 people. The population grows by 20% every year. What will the population be after 1 year?
18. 18.Find the compound interest on ₹52100 at 5% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 50000 people. The population grows by 8% every year. What will the population be after 2 years?
20. 20.What is the difference between the compound interest and the simple interest on ₹48800 at 15% per year for 2 years (in ₹)?
21. 21.What amount will ₹12000 grow to in 3 years at 10% per year compound interest (in ₹)?
22. 22.What amount will ₹59000 grow to in 3 years at 20% per year compound interest (in ₹)?
23. 23.A scooter is worth ₹21000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
25. 25.What amount will ₹17700 grow to in 1 year at 12% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹31800 at 8% per year for 1 year, compounded every year (in ₹).
27. 27.A scooter is worth ₹46000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
28. 28.What amount will ₹58400 grow to in 2 years at 5% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹22500 at 8% per year for 1 year, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹59200 at 15% per year for 2 years (in ₹)?
31. 31.A town has 54800 people. The population grows by 5% every year. What will the population be after 2 years?
32. 32.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹5200 at 5% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹25000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
36. 36.A town has 41200 people. The population grows by 5% every year. What will the population be after 2 years?
37. 37.Find the compound interest on ₹46800 at 25% per year for 2 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹20800 at 10% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹18500 at 10% per year for 2 years (in ₹)?
40. 40.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?

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