Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.A town has 20000 people. The population grows by 12% every year. What will the population be after 2 years?
- 2.Find the compound interest on ₹40000 at 20% per year for 3 years, compounded every year (in ₹).
- 3.Find the compound interest on ₹22400 at 15% per year for 2 years, compounded every year (in ₹).
- 4.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
- 5.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 6.Find the compound interest on ₹12300 at 20% per year for 2 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹36000 at 25% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹53500 at 12% per year for 1 year, compounded every year (in ₹).
- 9.What amount will ₹39600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 10.A scooter is worth ₹37200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 11.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
- 12.What amount will ₹13500 grow to in 1 year at 25% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹7200 at 5% per year for 2 years (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
- 15.What amount will ₹34400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 16.A town has 46300 people. The population grows by 8% every year. What will the population be after 1 year?
- 17.A town has 10400 people. The population grows by 20% every year. What will the population be after 1 year?
- 18.Find the compound interest on ₹57900 at 4% per year for 1 year, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹42200 at 15% per year for 1 year, compounded every year (in ₹).
- 21.What is the difference between the compound interest and the simple interest on ₹36000 at 5% per year for 2 years (in ₹)?
- 22.What amount will ₹39600 grow to in 1 year at 15% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹39600 at 25% per year for 2 years, compounded every year (in ₹).
- 24.A town has 44000 people. The population grows by 15% every year. What will the population be after 2 years?
- 25.What is the difference between the compound interest and the simple interest on ₹59600 at 15% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹19200 at 5% per year for 2 years, compounded every year (in ₹).
- 27.What amount will ₹41000 grow to in 2 years at 10% per year compound interest (in ₹)?
- 28.What amount will ₹38400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹56800 at 5% per year for 2 years (in ₹)?
- 30.What amount will ₹31000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 31.A town has 12500 people. The population grows by 25% every year. What will the population be after 1 year?
- 32.What is the difference between the compound interest and the simple interest on ₹20100 at 20% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹14900 at 25% per year for 1 year, compounded every year (in ₹).
- 34.Find the compound interest on ₹48800 at 25% per year for 1 year, compounded every year (in ₹).
- 35.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
- 36.Find the compound interest on ₹46500 at 10% per year for 1 year, compounded every year (in ₹).
- 37.A town has 15000 people. The population grows by 4% every year. What will the population be after 2 years?
- 38.A town has 17600 people. The population grows by 25% every year. What will the population be after 3 years?
- 39.A scooter is worth ₹21200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 40.A scooter is worth ₹34300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
Answer key
- 25088
- 29120
- 7224
- 38
- 3783
- 5412
- 2250
- 6420
- 47916
- 26877
- 27450
- 16875
- 18
- 1025
- 45494
- 50004
- 12480
- 2316
- 648
- 6330
- 90
- 45540
- 22275
- 58190
- 1341
- 1968
- 49610
- 50784
- 142
- 41261
- 15625
- 804
- 3725
- 12200
- 37044
- 4650
- 16224
- 34375
- 19133
- 27783
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