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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 521 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 20000 people. The population grows by 12% every year. What will the population be after 2 years?
  2. 2.Find the compound interest on ₹40000 at 20% per year for 3 years, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹22400 at 15% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹12300 at 20% per year for 2 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹36000 at 25% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹53500 at 12% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹39600 grow to in 2 years at 10% per year compound interest (in ₹)?
  10. 10.A scooter is worth ₹37200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  11. 11.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
  12. 12.What amount will ₹13500 grow to in 1 year at 25% per year compound interest (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹7200 at 5% per year for 2 years (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
  15. 15.What amount will ₹34400 grow to in 2 years at 15% per year compound interest (in ₹)?
  16. 16.A town has 46300 people. The population grows by 8% every year. What will the population be after 1 year?
  17. 17.A town has 10400 people. The population grows by 20% every year. What will the population be after 1 year?
  18. 18.Find the compound interest on ₹57900 at 4% per year for 1 year, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹42200 at 15% per year for 1 year, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹36000 at 5% per year for 2 years (in ₹)?
  22. 22.What amount will ₹39600 grow to in 1 year at 15% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹39600 at 25% per year for 2 years, compounded every year (in ₹).
  24. 24.A town has 44000 people. The population grows by 15% every year. What will the population be after 2 years?
  25. 25.What is the difference between the compound interest and the simple interest on ₹59600 at 15% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹19200 at 5% per year for 2 years, compounded every year (in ₹).
  27. 27.What amount will ₹41000 grow to in 2 years at 10% per year compound interest (in ₹)?
  28. 28.What amount will ₹38400 grow to in 2 years at 15% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹56800 at 5% per year for 2 years (in ₹)?
  30. 30.What amount will ₹31000 grow to in 3 years at 10% per year compound interest (in ₹)?
  31. 31.A town has 12500 people. The population grows by 25% every year. What will the population be after 1 year?
  32. 32.What is the difference between the compound interest and the simple interest on ₹20100 at 20% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹14900 at 25% per year for 1 year, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹48800 at 25% per year for 1 year, compounded every year (in ₹).
  35. 35.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
  36. 36.Find the compound interest on ₹46500 at 10% per year for 1 year, compounded every year (in ₹).
  37. 37.A town has 15000 people. The population grows by 4% every year. What will the population be after 2 years?
  38. 38.A town has 17600 people. The population grows by 25% every year. What will the population be after 3 years?
  39. 39.A scooter is worth ₹21200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  40. 40.A scooter is worth ₹34300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 25088
  2. 29120
  3. 7224
  4. 38
  5. 3783
  6. 5412
  7. 2250
  8. 6420
  9. 47916
  10. 26877
  11. 27450
  12. 16875
  13. 18
  14. 1025
  15. 45494
  16. 50004
  17. 12480
  18. 2316
  19. 648
  20. 6330
  21. 90
  22. 45540
  23. 22275
  24. 58190
  25. 1341
  26. 1968
  27. 49610
  28. 50784
  29. 142
  30. 41261
  31. 15625
  32. 804
  33. 3725
  34. 12200
  35. 37044
  36. 4650
  37. 16224
  38. 34375
  39. 19133
  40. 27783

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