Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 522 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
2. 2.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
3. 3.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
4. 4.What amount will ₹14400 grow to in 3 years at 25% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹49200 at 10% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹12800 at 5% per year for 2 years (in ₹)?
9. 9.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹14800 at 5% per year for 2 years, compounded every year (in ₹).
11. 11.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
12. 12.A scooter is worth ₹2600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹23300 at 10% per year for 2 years (in ₹)?
14. 14.A town has 32700 people. The population grows by 12% every year. What will the population be after 1 year?
15. 15.A scooter is worth ₹19800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
16. 16.Find the compound interest on ₹20600 at 10% per year for 2 years, compounded every year (in ₹).
17. 17.A scooter is worth ₹52200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
18. 18.What amount will ₹58400 grow to in 2 years at 5% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹20800 at 25% per year for 2 years (in ₹)?
20. 20.A town has 50100 people. The population grows by 8% every year. What will the population be after 1 year?
21. 21.What amount will ₹24800 grow to in 1 year at 15% per year compound interest (in ₹)?
22. 22.A town has 30400 people. The population grows by 15% every year. What will the population be after 2 years?
23. 23.What amount will ₹2700 grow to in 1 year at 8% per year compound interest (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹8500 at 10% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
26. 26.What amount will ₹4000 grow to in 2 years at 15% per year compound interest (in ₹)?
27. 27.What amount will ₹59700 grow to in 2 years at 10% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹45600 at 5% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹25900 at 8% per year for 1 year, compounded every year (in ₹).
30. 30.What amount will ₹54000 grow to in 2 years at 5% per year compound interest (in ₹)?
31. 31.What amount will ₹9200 grow to in 2 years at 25% per year compound interest (in ₹)?
32. 32.A town has 43800 people. The population grows by 12% every year. What will the population be after 1 year?
33. 33.What is the difference between the compound interest and the simple interest on ₹34400 at 25% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹18400 at 5% per year for 2 years, compounded every year (in ₹).
35. 35.What amount will ₹11500 grow to in 1 year at 25% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹14100 at 4% per year for 1 year, compounded every year (in ₹).
37. 37.What amount will ₹37100 grow to in 1 year at 5% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹33000 at 10% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹12000 at 25% per year for 2 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹10200 at 10% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets