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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 523 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹16400 at 25% per year for 1 year, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹3900 at 20% per year for 2 years (in ₹)?
  3. 3.What amount will ₹60000 grow to in 2 years at 15% per year compound interest (in ₹)?
  4. 4.What amount will ₹36000 grow to in 2 years at 5% per year compound interest (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹8000 at 15% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹15200 at 15% per year for 2 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹42700 at 20% per year for 1 year, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹59700 at 20% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
  10. 10.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
  11. 11.A town has 28500 people. The population grows by 5% every year. What will the population be after 1 year?
  12. 12.What is the difference between the compound interest and the simple interest on ₹5500 at 20% per year for 2 years (in ₹)?
  13. 13.What amount will ₹50400 grow to in 2 years at 15% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹47500 at 5% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
  16. 16.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹17200 at 15% per year for 2 years (in ₹)?
  18. 18.A town has 17000 people. The population grows by 20% every year. What will the population be after 3 years?
  19. 19.A scooter is worth ₹22700. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  20. 20.Find the compound interest on ₹51100 at 25% per year for 1 year, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹22000 at 10% per year for 2 years (in ₹)?
  22. 22.What amount will ₹27500 grow to in 2 years at 12% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹4000 at 5% per year for 2 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹7300 at 5% per year for 1 year, compounded every year (in ₹).
  26. 26.A town has 11900 people. The population grows by 15% every year. What will the population be after 1 year?
  27. 27.What amount will ₹57300 grow to in 1 year at 20% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹29200 at 5% per year for 2 years (in ₹)?
  29. 29.A scooter is worth ₹10000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹25200 at 25% per year for 1 year, compounded every year (in ₹).
  32. 32.What is the difference between the compound interest and the simple interest on ₹3600 at 15% per year for 2 years (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹24900 at 10% per year for 2 years (in ₹)?
  34. 34.A town has 20000 people. The population grows by 15% every year. What will the population be after 2 years?
  35. 35.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  36. 36.What amount will ₹46500 grow to in 3 years at 20% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  38. 38.A town has 52300 people. The population grows by 10% every year. What will the population be after 1 year?
  39. 39.What is the difference between the compound interest and the simple interest on ₹6100 at 20% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹20100 at 20% per year for 2 years (in ₹)?

Answer key

  1. 4100
  2. 156
  3. 79350
  4. 39690
  5. 180
  6. 4902
  7. 8540
  8. 2388
  9. 576
  10. 37500
  11. 29925
  12. 220
  13. 66654
  14. 2375
  15. 64
  16. 636
  17. 387
  18. 29376
  19. 18160
  20. 12775
  21. 220
  22. 34496
  23. 410
  24. 4167
  25. 365
  26. 13685
  27. 68760
  28. 73
  29. 9025
  30. 80
  31. 6300
  32. 81
  33. 249
  34. 26450
  35. 12
  36. 80352
  37. 6305
  38. 57530
  39. 244
  40. 804

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