Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 536 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹11800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
4. 4.What amount will ₹40000 grow to in 2 years at 5% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
6. 6.A town has 3200 people. The population grows by 15% every year. What will the population be after 2 years?
7. 7.Find the compound interest on ₹14000 at 20% per year for 3 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹49100 at 10% per year for 2 years (in ₹)?
9. 9.What amount will ₹56000 grow to in 2 years at 15% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹55000 at 10% per year for 1 year, compounded every year (in ₹).
11. 11.A scooter is worth ₹29400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹29600 at 10% per year for 2 years (in ₹)?
13. 13.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
14. 14.What amount will ₹53200 grow to in 2 years at 5% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
16. 16.A town has 3600 people. The population grows by 5% every year. What will the population be after 1 year?
17. 17.A town has 31100 people. The population grows by 25% every year. What will the population be after 1 year?
18. 18.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹49600 at 25% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹58000 at 5% per year for 2 years (in ₹)?
21. 21.What amount will ₹57000 grow to in 3 years at 10% per year compound interest (in ₹)?
22. 22.A town has 53000 people. The population grows by 8% every year. What will the population be after 1 year?
23. 23.A scooter is worth ₹24000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
24. 24.What amount will ₹37200 grow to in 1 year at 15% per year compound interest (in ₹)?
25. 25.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
26. 26.What amount will ₹43300 grow to in 1 year at 12% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹32800 at 15% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹31200 at 15% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹42000 at 25% per year for 2 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹16000 at 15% per year for 2 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹25600 at 25% per year for 2 years (in ₹)?
34. 34.What amount will ₹13600 grow to in 2 years at 5% per year compound interest (in ₹)?
35. 35.What amount will ₹18000 grow to in 2 years at 20% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹30000 at 25% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹2300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
40. 40.A scooter is worth ₹45000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?

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