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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 537 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 53700 people. The population grows by 20% every year. What will the population be after 1 year?
  2. 2.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
  3. 3.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
  5. 5.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
  6. 6.What amount will ₹25800 grow to in 2 years at 20% per year compound interest (in ₹)?
  7. 7.Find the compound interest on ₹10500 at 20% per year for 2 years, compounded every year (in ₹).
  8. 8.A town has 39900 people. The population grows by 15% every year. What will the population be after 1 year?
  9. 9.A scooter is worth ₹39800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  10. 10.What amount will ₹45600 grow to in 2 years at 10% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹7300 at 10% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹14500 at 4% per year for 1 year, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹18100 at 5% per year for 1 year, compounded every year (in ₹).
  14. 14.A town has 26000 people. The population grows by 4% every year. What will the population be after 1 year?
  15. 15.Find the compound interest on ₹23000 at 12% per year for 1 year, compounded every year (in ₹).
  16. 16.What amount will ₹48900 grow to in 2 years at 10% per year compound interest (in ₹)?
  17. 17.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  19. 19.A scooter is worth ₹11500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
  21. 21.What amount will ₹4400 grow to in 1 year at 20% per year compound interest (in ₹)?
  22. 22.What amount will ₹56000 grow to in 2 years at 25% per year compound interest (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹4700 at 20% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹3000 at 8% per year for 1 year, compounded every year (in ₹).
  25. 25.A scooter is worth ₹58600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  26. 26.What amount will ₹11200 grow to in 2 years at 5% per year compound interest (in ₹)?
  27. 27.What amount will ₹35100 grow to in 1 year at 4% per year compound interest (in ₹)?
  28. 28.What amount will ₹22000 grow to in 3 years at 10% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹36200 at 20% per year for 1 year, compounded every year (in ₹).
  32. 32.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
  33. 33.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹21500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  35. 35.Find the compound interest on ₹56500 at 25% per year for 1 year, compounded every year (in ₹).
  36. 36.A scooter is worth ₹15000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  37. 37.Find the compound interest on ₹17300 at 8% per year for 1 year, compounded every year (in ₹).
  38. 38.A scooter is worth ₹12900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  39. 39.A town has 40600 people. The population grows by 20% every year. What will the population be after 2 years?
  40. 40.A scooter is worth ₹28200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 64440
  2. 12167
  3. 25002
  4. 72
  5. 109375
  6. 37152
  7. 4620
  8. 45885
  9. 32238
  10. 55176
  11. 73
  12. 580
  13. 905
  14. 27040
  15. 2760
  16. 59169
  17. 37044
  18. 336
  19. 5888
  20. 80
  21. 5280
  22. 87500
  23. 188
  24. 240
  25. 37504
  26. 12348
  27. 36504
  28. 29282
  29. 180
  30. 864
  31. 7240
  32. 36501
  33. 64827
  34. 19780
  35. 14125
  36. 11616
  37. 1384
  38. 12255
  39. 58464
  40. 24816

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