Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 538 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹39400 at 10% per year for 2 years, compounded every year (in ₹).
2. 2.A town has 56000 people. The population grows by 10% every year. What will the population be after 2 years?
3. 3.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
5. 5.Find the compound interest on ₹54700 at 5% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹14400 at 25% per year for 2 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹47000 at 10% per year for 2 years, compounded every year (in ₹).
10. 10.A scooter is worth ₹32500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
12. 12.A town has 24800 people. The population grows by 5% every year. What will the population be after 1 year?
13. 13.What amount will ₹8900 grow to in 1 year at 20% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹30000 at 10% per year for 1 year, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹33800 at 10% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹37300 at 12% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
20. 20.What amount will ₹35200 grow to in 1 year at 20% per year compound interest (in ₹)?
21. 21.A town has 12600 people. The population grows by 5% every year. What will the population be after 1 year?
22. 22.Find the compound interest on ₹9000 at 20% per year for 3 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹43500 at 20% per year for 3 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹25700 at 12% per year for 1 year, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹2300 at 10% per year for 2 years (in ₹)?
26. 26.What amount will ₹35800 grow to in 2 years at 10% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹47500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
28. 28.Find the compound interest on ₹41900 at 8% per year for 1 year, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
30. 30.A scooter is worth ₹3200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
31. 31.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹37100 at 10% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹43800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
34. 34.Find the compound interest on ₹22400 at 25% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹23500 at 25% per year for 1 year, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹23600 at 5% per year for 2 years (in ₹)?
37. 37.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
38. 38.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹37200 at 5% per year for 2 years, compounded every year (in ₹).

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