Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 541 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹24100 grow to in 1 year at 20% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹18900 at 20% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹38800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
5. 5.A town has 51300 people. The population grows by 20% every year. What will the population be after 2 years?
6. 6.What amount will ₹12700 grow to in 2 years at 10% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹36600 at 20% per year for 2 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹17600 at 5% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹34900 at 20% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
12. 12.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
13. 13.What is the difference between the compound interest and the simple interest on ₹56500 at 20% per year for 2 years (in ₹)?
14. 14.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
15. 15.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
16. 16.Find the compound interest on ₹51300 at 4% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹34000 grow to in 2 years at 5% per year compound interest (in ₹)?
18. 18.What amount will ₹6800 grow to in 2 years at 5% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹22500 at 10% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹40100 at 8% per year for 1 year, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹36400 at 25% per year for 2 years (in ₹)?
22. 22.What amount will ₹37100 grow to in 1 year at 8% per year compound interest (in ₹)?
23. 23.A scooter is worth ₹1600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
25. 25.A town has 22500 people. The population grows by 4% every year. What will the population be after 2 years?
26. 26.What amount will ₹4200 grow to in 1 year at 10% per year compound interest (in ₹)?
27. 27.A town has 2300 people. The population grows by 8% every year. What will the population be after 1 year?
28. 28.Find the compound interest on ₹57800 at 15% per year for 1 year, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹3200 at 15% per year for 2 years, compounded every year (in ₹).
32. 32.A town has 21200 people. The population grows by 15% every year. What will the population be after 2 years?
33. 33.What amount will ₹24800 grow to in 2 years at 10% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹12900 at 10% per year for 2 years, compounded every year (in ₹).
35. 35.Find the compound interest on ₹52100 at 20% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹34600 at 10% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 18800 people. The population grows by 5% every year. What will the population be after 2 years?
38. 38.What amount will ₹16900 grow to in 1 year at 10% per year compound interest (in ₹)?
39. 39.A town has 42000 people. The population grows by 20% every year. What will the population be after 3 years?
40. 40.What amount will ₹51300 grow to in 1 year at 10% per year compound interest (in ₹)?

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