Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 557 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 54000 people. The population grows by 5% every year. What will the population be after 2 years?
2. 2.What amount will ₹41600 grow to in 2 years at 5% per year compound interest (in ₹)?
3. 3.A scooter is worth ₹2000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
4. 4.What amount will ₹41400 grow to in 1 year at 10% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
6. 6.What amount will ₹2900 grow to in 1 year at 20% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹17100 at 20% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
9. 9.What amount will ₹9600 grow to in 1 year at 25% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹5600 at 20% per year for 2 years (in ₹)?
11. 11.A scooter is worth ₹41000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
12. 12.Find the compound interest on ₹12800 at 20% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹41000 at 20% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹49900 at 8% per year for 1 year, compounded every year (in ₹).
15. 15.A scooter is worth ₹32000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
16. 16.Find the compound interest on ₹42000 at 20% per year for 3 years, compounded every year (in ₹).
17. 17.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹44800 at 25% per year for 3 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹53200 at 15% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹50400 at 25% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹27200 at 5% per year for 2 years (in ₹)?
22. 22.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹20000 at 20% per year for 3 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹51200 at 15% per year for 2 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
26. 26.What amount will ₹23600 grow to in 2 years at 25% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
28. 28.A town has 29300 people. The population grows by 12% every year. What will the population be after 1 year?
29. 29.Find the compound interest on ₹26800 at 15% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹56000 at 15% per year for 2 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹28000 at 15% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹25200 at 5% per year for 2 years (in ₹)?
34. 34.What amount will ₹4300 grow to in 1 year at 25% per year compound interest (in ₹)?
35. 35.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
36. 36.A town has 6700 people. The population grows by 20% every year. What will the population be after 1 year?
37. 37.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
38. 38.What amount will ₹57500 grow to in 1 year at 10% per year compound interest (in ₹)?
39. 39.A town has 45600 people. The population grows by 10% every year. What will the population be after 1 year?
40. 40.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?

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