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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 558 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹49900 at 10% per year for 2 years, compounded every year (in ₹).
  2. 2.A town has 36500 people. The population grows by 20% every year. What will the population be after 3 years?
  3. 3.What is the difference between the compound interest and the simple interest on ₹6400 at 15% per year for 2 years (in ₹)?
  4. 4.A scooter is worth ₹6100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹32800 at 15% per year for 2 years (in ₹)?
  6. 6.What amount will ₹18000 grow to in 3 years at 10% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹46800 at 25% per year for 2 years (in ₹)?
  8. 8.What amount will ₹8000 grow to in 3 years at 10% per year compound interest (in ₹)?
  9. 9.What amount will ₹9600 grow to in 1 year at 5% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹6800 at 5% per year for 1 year, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹48400 at 25% per year for 2 years (in ₹)?
  13. 13.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹47200 at 25% per year for 2 years, compounded every year (in ₹).
  15. 15.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
  16. 16.What amount will ₹52000 grow to in 3 years at 20% per year compound interest (in ₹)?
  17. 17.A town has 8300 people. The population grows by 12% every year. What will the population be after 1 year?
  18. 18.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹57600 at 25% per year for 2 years, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹55600 at 10% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹55600 at 5% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹4100 at 25% per year for 1 year, compounded every year (in ₹).
  23. 23.A scooter is worth ₹7800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  24. 24.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹18000 at 20% per year for 1 year, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹19400 at 10% per year for 2 years (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
  30. 30.What amount will ₹49000 grow to in 3 years at 10% per year compound interest (in ₹)?
  31. 31.A scooter is worth ₹60000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  32. 32.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹33500 at 25% per year for 1 year, compounded every year (in ₹).
  34. 34.What amount will ₹58500 grow to in 1 year at 10% per year compound interest (in ₹)?
  35. 35.A scooter is worth ₹22000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  36. 36.What amount will ₹16400 grow to in 2 years at 25% per year compound interest (in ₹)?
  37. 37.What amount will ₹44700 grow to in 2 years at 10% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹9900 at 10% per year for 2 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹13600 at 25% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 10479
  2. 63072
  3. 144
  4. 4941
  5. 738
  6. 23958
  7. 2925
  8. 10648
  9. 10080
  10. 96
  11. 340
  12. 3025
  13. 1986
  14. 26550
  15. 85169
  16. 89856
  17. 9296
  18. 1261
  19. 32400
  20. 556
  21. 139
  22. 1025
  23. 7410
  24. 6289
  25. 3600
  26. 29169
  27. 194
  28. 240
  29. 352
  30. 65219
  31. 46464
  32. 12544
  33. 8375
  34. 64350
  35. 20900
  36. 25625
  37. 54087
  38. 1250
  39. 2079
  40. 3400

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