← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 569 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A town has 12800 people. The population grows by 5% every year. What will the population be after 2 years?
  2. 2.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹28400 at 20% per year for 1 year, compounded every year (in ₹).
  5. 5.What amount will ₹11800 grow to in 1 year at 15% per year compound interest (in ₹)?
  6. 6.What amount will ₹53400 grow to in 1 year at 15% per year compound interest (in ₹)?
  7. 7.A town has 13500 people. The population grows by 25% every year. What will the population be after 1 year?
  8. 8.Find the compound interest on ₹43200 at 15% per year for 2 years, compounded every year (in ₹).
  9. 9.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
  10. 10.A scooter is worth ₹41500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  11. 11.What amount will ₹8400 grow to in 1 year at 4% per year compound interest (in ₹)?
  12. 12.Find the compound interest on ₹14000 at 5% per year for 2 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹19100 at 20% per year for 2 years (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹41300 at 20% per year for 2 years (in ₹)?
  15. 15.A town has 12100 people. The population grows by 4% every year. What will the population be after 1 year?
  16. 16.A scooter is worth ₹34000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  17. 17.Find the compound interest on ₹15700 at 12% per year for 1 year, compounded every year (in ₹).
  18. 18.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹56400 at 25% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
  21. 21.A scooter is worth ₹6700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  22. 22.What amount will ₹14400 grow to in 2 years at 15% per year compound interest (in ₹)?
  23. 23.What amount will ₹47600 grow to in 2 years at 25% per year compound interest (in ₹)?
  24. 24.What amount will ₹24100 grow to in 2 years at 20% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹46800 at 15% per year for 2 years, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  27. 27.A scooter is worth ₹42300. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
  30. 30.Find the compound interest on ₹45200 at 10% per year for 1 year, compounded every year (in ₹).
  31. 31.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹22500 at 20% per year for 1 year, compounded every year (in ₹).
  34. 34.What amount will ₹19000 grow to in 2 years at 10% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹59500 at 20% per year for 3 years, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹5200 at 25% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹50400 at 15% per year for 2 years, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?

Answer key

  1. 14112
  2. 336
  3. 68
  4. 5680
  5. 13570
  6. 61410
  7. 16875
  8. 13932
  9. 24334
  10. 39425
  11. 8736
  12. 1435
  13. 764
  14. 1652
  15. 12584
  16. 24786
  17. 1884
  18. 29744
  19. 3525
  20. 176
  21. 5025
  22. 19044
  23. 74375
  24. 34704
  25. 15093
  26. 6305
  27. 38916
  28. 44
  29. 72
  30. 4520
  31. 27436
  32. 288
  33. 4500
  34. 22990
  35. 43316
  36. 325
  37. 2317
  38. 180
  39. 16254
  40. 112

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets