Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 573 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 27300 people. The population grows by 10% every year. What will the population be after 2 years?
2. 2.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
3. 3.A town has 8500 people. The population grows by 20% every year. What will the population be after 3 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹14400 at 25% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹58000 at 10% per year for 3 years, compounded every year (in ₹).
6. 6.A scooter is worth ₹2500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹49000 at 10% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹5000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
9. 9.Find the compound interest on ₹58400 at 8% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹13400 at 10% per year for 2 years, compounded every year (in ₹).
11. 11.What amount will ₹24900 grow to in 1 year at 12% per year compound interest (in ₹)?
12. 12.What amount will ₹8500 grow to in 1 year at 8% per year compound interest (in ₹)?
13. 13.What amount will ₹3100 grow to in 1 year at 15% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹2500 at 5% per year for 1 year, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
16. 16.A town has 15400 people. The population grows by 20% every year. What will the population be after 2 years?
17. 17.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹57000 at 10% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
20. 20.What amount will ₹18200 grow to in 1 year at 20% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹13600 at 25% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹23200 grow to in 2 years at 5% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹54700 at 5% per year for 1 year, compounded every year (in ₹).
24. 24.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
25. 25.What amount will ₹32500 grow to in 2 years at 4% per year compound interest (in ₹)?
26. 26.A scooter is worth ₹13600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹45700 at 20% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹25600 at 15% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
30. 30.A scooter is worth ₹15000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹29200 at 5% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹3600 at 5% per year for 2 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹23200 at 5% per year for 2 years (in ₹)?
34. 34.A town has 2900 people. The population grows by 20% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹14000 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹34800 grow to in 1 year at 20% per year compound interest (in ₹)?
37. 37.A town has 44000 people. The population grows by 5% every year. What will the population be after 1 year?
38. 38.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
39. 39.A scooter is worth ₹24000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
40. 40.Find the compound interest on ₹11600 at 15% per year for 2 years, compounded every year (in ₹).

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