Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 578 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
2. 2.A town has 53400 people. The population grows by 25% every year. What will the population be after 1 year?
3. 3.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹50300 at 10% per year for 1 year, compounded every year (in ₹).
5. 5.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
6. 6.What is the difference between the compound interest and the simple interest on ₹36700 at 20% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
8. 8.A town has 42500 people. The population grows by 8% every year. What will the population be after 2 years?
9. 9.A town has 2300 people. The population grows by 10% every year. What will the population be after 1 year?
10. 10.What amount will ₹39500 grow to in 3 years at 20% per year compound interest (in ₹)?
11. 11.What amount will ₹36200 grow to in 2 years at 10% per year compound interest (in ₹)?
12. 12.A town has 50200 people. The population grows by 8% every year. What will the population be after 1 year?
13. 13.What amount will ₹26400 grow to in 1 year at 20% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
15. 15.A scooter is worth ₹54000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
16. 16.A town has 5000 people. The population grows by 4% every year. What will the population be after 1 year?
17. 17.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
20. 20.A town has 20000 people. The population grows by 12% every year. What will the population be after 2 years?
21. 21.A town has 40800 people. The population grows by 15% every year. What will the population be after 2 years?
22. 22.A scooter is worth ₹56100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
23. 23.What amount will ₹40200 grow to in 1 year at 4% per year compound interest (in ₹)?
24. 24.What amount will ₹16800 grow to in 1 year at 5% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹4800 at 15% per year for 2 years (in ₹)?
27. 27.A town has 4900 people. The population grows by 12% every year. What will the population be after 1 year?
28. 28.A town has 49000 people. The population grows by 20% every year. What will the population be after 3 years?
29. 29.What amount will ₹11600 grow to in 2 years at 15% per year compound interest (in ₹)?
30. 30.A town has 5800 people. The population grows by 20% every year. What will the population be after 2 years?
31. 31.Find the compound interest on ₹58500 at 10% per year for 2 years, compounded every year (in ₹).
32. 32.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
33. 33.Find the compound interest on ₹45900 at 5% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹28700 grow to in 1 year at 12% per year compound interest (in ₹)?
35. 35.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹27500 at 10% per year for 2 years (in ₹)?
37. 37.A town has 35000 people. The population grows by 10% every year. What will the population be after 3 years?
38. 38.A scooter is worth ₹41500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
39. 39.What amount will ₹57000 grow to in 3 years at 10% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹35600 at 10% per year for 2 years, compounded every year (in ₹).

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