Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 2.What amount will ₹12400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
- 4.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
- 5.A town has 6000 people. The population grows by 25% every year. What will the population be after 2 years?
- 6.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
- 8.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
- 10.A town has 36000 people. The population grows by 10% every year. What will the population be after 3 years?
- 11.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 12.A scooter is worth ₹32500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 13.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
- 17.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 18.What amount will ₹32200 grow to in 2 years at 20% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹39600 at 25% per year for 2 years (in ₹)?
- 20.A town has 3000 people. The population grows by 20% every year. What will the population be after 1 year?
- 21.What amount will ₹8000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 22.What amount will ₹40000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
- 25.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
- 27.What amount will ₹32400 grow to in 2 years at 10% per year compound interest (in ₹)?
- 28.Find the compound interest on ₹7700 at 10% per year for 1 year, compounded every year (in ₹).
- 29.A scooter is worth ₹57800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 30.A scooter is worth ₹37500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹17600 at 15% per year for 2 years (in ₹)?
- 32.A town has 45700 people. The population grows by 20% every year. What will the population be after 2 years?
- 33.A scooter is worth ₹56800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 34.What amount will ₹24500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 35.A scooter is worth ₹22800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 36.Find the compound interest on ₹57900 at 20% per year for 1 year, compounded every year (in ₹).
- 37.Find the compound interest on ₹49400 at 4% per year for 1 year, compounded every year (in ₹).
- 38.Find the compound interest on ₹46100 at 25% per year for 1 year, compounded every year (in ₹).
- 39.Find the compound interest on ₹44000 at 10% per year for 3 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹37300 at 12% per year for 1 year, compounded every year (in ₹).
Answer key
- 13718
- 16399
- 13356
- 1272
- 9375
- 720
- 64
- 12167
- 24
- 47916
- 48
- 16640
- 25002
- 80
- 20835
- 3816
- 34992
- 46368
- 2475
- 3600
- 8820
- 50176
- 336
- 288
- 49572
- 320
- 39204
- 770
- 50864
- 31740
- 396
- 65808
- 41038
- 42336
- 20577
- 11580
- 1976
- 11525
- 14564
- 4476
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