Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 585 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹32200 at 12% per year for 1 year, compounded every year (in ₹).
2. 2.What amount will ₹48100 grow to in 1 year at 12% per year compound interest (in ₹)?
3. 3.A town has 25900 people. The population grows by 8% every year. What will the population be after 1 year?
4. 4.What amount will ₹47700 grow to in 1 year at 25% per year compound interest (in ₹)?
5. 5.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
6. 6.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹59200 at 25% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹5300 at 10% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹18400 at 5% per year for 1 year, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹36000 at 15% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
13. 13.A town has 40300 people. The population grows by 10% every year. What will the population be after 1 year?
14. 14.Find the compound interest on ₹35400 at 12% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹16000 at 25% per year for 2 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹18700 at 10% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹4300 at 10% per year for 2 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹20300 at 12% per year for 1 year, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
20. 20.What amount will ₹18000 grow to in 1 year at 8% per year compound interest (in ₹)?
21. 21.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
22. 22.A town has 21100 people. The population grows by 20% every year. What will the population be after 2 years?
23. 23.Find the compound interest on ₹36000 at 20% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹51500 at 10% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹9600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
27. 27.What amount will ₹3100 grow to in 1 year at 10% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹32000 at 4% per year for 1 year, compounded every year (in ₹).
29. 29.What amount will ₹52000 grow to in 3 years at 10% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹17100 at 20% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹28000 at 5% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹53100 at 20% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹4800 at 5% per year for 1 year, compounded every year (in ₹).
34. 34.Find the compound interest on ₹51200 at 25% per year for 3 years, compounded every year (in ₹).
35. 35.A town has 27500 people. The population grows by 8% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹38400 at 25% per year for 3 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹12200 at 5% per year for 1 year, compounded every year (in ₹).
38. 38.Find the compound interest on ₹28600 at 8% per year for 1 year, compounded every year (in ₹).
39. 39.A town has 32500 people. The population grows by 15% every year. What will the population be after 1 year?
40. 40.What amount will ₹10800 grow to in 2 years at 25% per year compound interest (in ₹)?

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